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astraxan [27]
3 years ago
14

Explain why the term of the expression are 2x and 8 not x and 8?

Mathematics
1 answer:
LuckyWell [14K]3 years ago
7 0

Answer:

because 2x is a variable and 8 is just a constant......am i right or no

Step-by-step explanation:

<3 ya have a nice day you sweetie pie munchkins

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This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex
velikii [3]

Answer:

The maximum value= 36

Minimum value = - 36

Step-by-step explanation:

Given that

f(x, y, z) = 8 x + 8 y + 4 z

h(x,y,z)=4 x² + 4 y² + 4 z² - 36

From Lagrange multipliers

Δf = λ Δh

Δf = < 8 ,8 , 4>

Δh = < 8 x ,8 y  , 8 z>

Δf = λ Δh

So

< 8 ,8 , 4> = < 8  λ x ,8 λ y  , 8 λ z>

8 = 8  λ x                     -------------1

8 = 8 λ y                      ----  ------2

4 = 8 λ z                    ----------------3

From equation 1 ,2 and 3

Now by putting the value of x,y and z in the following equation

4 x² + 4 y² + 4 z² = 36

4\times \dfrac{1}{\lambda^2 }+4\times \dfrac{1}{\lambda^2 }+4\times \dfrac{1}{(2\lambda)^2 }=36

\dfrac{4}{\lambda^2 }+ \dfrac{4}{\lambda^2 }+ \dfrac{1}{\lambda^2 }=36

So the value of λ is

\lambda =\pm \dfrac{1}{2}

When λ = 1/2

x = 1 / λ   , y=1 / λ   ,  z= 1 /2 λ

x= 2 , y = 2 , z=1

So

f(x, y, z) = 8 x + 8 y + 4 z

f(2, 2, 1) = 8 x 2 + 8 x 2 + 4 x 1

f(2, 2, 1) =36

When λ = - 1/2

x = 1 / λ   , y=1 / λ   ,  z= 1 /2 λ

x= - 2 , y = - 2 , z= - 1

So

f(x, y, z) = 8 x + 8 y + 4 z

f(-2, -2, -1) = 8 x (-2) + 8 x (-2) + 4 x (-1)

f(-2, -2, -1) = - 36

The maximum value= 36

Minimum value = - 36

7 0
3 years ago
Read 2 more answers
What is 10 to the 8th power multiplied by 30 subtract 3
IceJOKER [234]

Answer:

21

Step-by-step explanation:

4 0
2 years ago
Help me solve this please
shutvik [7]

Answer:

D'G' = 52.5 units

Step-by-step explanation:

Since the dilatation is centred at the origin then multiply the original coordinates by the scale factor 3.5

D' = (1 × 3.5, 7 × 3.5 ) = (3.5, 24.5 )

G' = (- 8 × 3.5, - 5 × 3.5 ) = (- 28, - 17.5 )

Calculate D'G' using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = D' (3.5, 24.5) and (x₂, y₂ ) = G' (- 28, - 17.5)

D'G' = \sqrt{(-28-3.5)^2+(-17.5-24.5)^2}

       = \sqrt{(-31.5)^2+42^2}

       = \sqrt{992.25+1764}

        = \sqrt{2756.25}

         = 52.5 units

7 0
2 years ago
If G(x) = 3x + 1, then G -1(1) is<br> 4<br> 1/3<br> 0
Eduardwww [97]

Answer:

0


Step-by-step explanation:

g(x) = 3x + 1 \\\ y = 3x + 1


Changing x to y and y to x:


x = 3y + 1 \\\ 3y = x - 1 \\\ y = \frac{x - 1}{3} \\\ g^{-1}(x) = \frac{x - 1}{3} \\\ g^{- 1} (1) = \frac{1 - 1}{3} \\\ g^{- 1} (1) = 0


I hope I helped you.

4 0
2 years ago
Martin was given 10 math problems, and he has answered 7 of them. What percent of the problems does Martin have left to do?
Artyom0805 [142]
Martin still has 30% of the problems left to do.
7 0
3 years ago
Read 2 more answers
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