Explain why the term of the expression are 2x and 8 not x and 8?

Mathematics

1 answer:

LuckyWell [14K]3 years ago

7 0

Answer:

because 2x is a variable and 8 is just a constant......am i right or no

Step-by-step explanation:

<3 ya have a nice day you sweetie pie munchkins

You might be interested in

An equation was used to predict the number of possible enrollments in an afterschool program for the first 6 months of the year.

AysviL [449]

55 + 80 + 95 + 100 +115 +90 =535 actual enrollments. 75 + 80 +85 +90 +95 + 100 = 525 predicted enrollments. 535 - 525 = 10 residuals.

6 0

3 years ago

How do I graph this <br>

disa [49]

Answer:

ight so you put a dot at -2 and then go up like, go up -2 line until you look across and it says 7 and put a dot there

Step-by-step explanation:

7 0

3 years ago

How do I write two trillion ninety nine in number form?

TiliK225 [7]

Answer:

here

Step-by-step explanation:

2.000.000.099

4 0

2 years ago

Which expression is equivalent to<br> logbase12 ((1/2)/8w)?

Lunna [17]

$\bf \begin{array}{llll} \textit{logarithm of factors} \\\\ log_a(xy)\implies log_a(x)+log_a(y) \end{array}~\hfill \begin{array}{llll} \textit{Logarithm of rationals} \\\\ log_a\left( \frac{x}{y}\right)\implies log_a(x)-log_a(y) \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \log_{12}\left( \cfrac{~~\frac{1}{2}~~}{8w} \right)\implies \begin{array}{llll} \log_{12}\left( \frac{1}{2} \right)&-&\log_{12}(8w)\\\\ \log_{12}(1)-\log_{12}(2)&-&[\log_{12}(8)+\log_{12}(w)] \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \log_{12}(1)-\log_{12}(2)-\log_{12}(8)-\log_{12}(w)~\hfill$

7 0

3 years ago

What is the sum?

iragen [17]

Answer:1.55?

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers