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nadya68 [22]
3 years ago
10

During a medication pass, the nurse notices that the health care provider ordered a dose of medication that appears to be excess

ive based on the nurse's knowledge of the medication. the nurse calls the provider, and the provider instructs the nurse to administer the medication anyway. what should the nurse do?
Biology
1 answer:
photoshop1234 [79]3 years ago
6 0
<span>If possible, the nurse should confirm the necessary dosage with the assigned doctor or another nurse on duty if the doctor is unavailable. If this is not feasible, the nurse should go with the recommendation from the provider as long as there are no conflicting allergies and relay the information to the doctor as soon as possible.</span>
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A normal breath takes in about 1.0 L of air. If air has an average molar mass of 28.8 g per 1 mol and has a density of 0.97 g/mL
Ann [662]

Taking into account the definition of density and Avogadro's Number, you take 2.0286×10²⁵ molecules of air.

<h3>What is density</h3>

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density=\frac{mass}{volume}

<h3>What is Avogadro's Number</h3>

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

<h3>Amount of molecules of air</h3>

In this case, you know that:

  • Density= 0.97 \frac{g}{mL}
  • Volume= 1 L= 1000 mL

Replacing in the definition of density:

0.97 \frac{g}{mL}=\frac{mass}{1000 mL}

Solving:

mass= 0.97 \frac{g}{mL}  ×1000 mL

<u><em>mass= 970 g</em></u>

Air has an average molar mass of 28.8 g per 1 mol. Then 970 grams are contained in 33.68 moles.

Now, considering the definition of Avogadro's number you can apply the following rule of three: If 1 mole of air contains 6.023×10²³ molecules, 33.68 moles contains how many molecules?

amount of molecules = (33.68 moles× 6.023×10²³ molecules)÷ 1 mole

<u><em>amount of molecules= 2.0286×10²⁵ molecules</em></u>

Finally, you take 2.0286×10²⁵ molecules of air.

Learn more about

density:

brainly.com/question/952755

brainly.com/question/1462554

Avogadro's Number:

brainly.com/question/11907018

brainly.com/question/1445383

brainly.com/question/1528951

#SPJ11

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1 year ago
Which statement correctly compares the use of bar graphs versus Circle graphs
Novosadov [1.4K]

Bar graphs show patterns in data with variables that change over time; Whereas pie charts, show data as parts out of a whole, (such as 100%).


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3 years ago
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Please please help me !!!!!!!!!!!!
ch4aika [34]

Hey there!

Your answer: Available Space

The question is asking, which of the following options would be a (limited source). We have to find a option that has a limited source, which means that there is a limit to something. Your answer is (b) because there are limited space with the spce that is already available. Air temperature would NOT be your answer.

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Monohybrid Mice, i need help
Katyanochek1 [597]

Answer/Explanation:

  • <em>See attached images showing the crosses on a Punnett square as well as the genotype and phenotypes of each cross.</em>

I. Cross between a female Gg with a male gg (GG X gg):

1. Probability of getting gray offspring (Gg) = 2/4 (¼+ ¼) = ½  

2. Probability of getting albino offspring (gg) = 2/4 (¼+ ¼) = ½

3. There are 2 possible genotypes among the offspring, which are Gg and gg.

4. There are 2 possible phenotypes among the offspring, which are gray and albino coat color.

5. Probability of getting heterozygous offspring (i.e. Gg) = 2/4 = ½

6. Probability of getting homozygous offspring (i.e. GG or gg) = Probability of getting GG + Probability of getting gg = ½ + 0 = ½  

7. The color of the female that was crossed (i.e. Gg), is gray color. The allele for gray coat color (G) is dominant over the allele for albino coat color (g).

8. The color of the male (gg) that was crossed is albino. The recessive allele (g) for albino coat color, in its homozygous state would express itself in the absence of the dominant G allele for gray color.

II. Cross between homozygous gray female with a heterozygous male (GG X Gg):

1. Probability of getting gray offspring (GG or Gg) = 4/4 (i.e. ¼+ ¼ + ¼ + ¼ ) = 1  

2. Probability of getting albino offspring (gg) = 0  

3. There are only 2 possible genotypes among the offspring, which are GG and Gg.

4. There is only 1 possible phenotype among the offspring, which is gray coat color.

5. Probability of getting heterozygous offspring (i.e. Gg) = 2/4 (i.e. ¼+ ¼ ) = ½

6. Probability of getting homozygous offspring (i.e. GG or gg) = Probability of getting GG + Probability of getting gg = 0 + ½  = ½  

7. The genotype of the female that was crossed is GG, given that the female is homozygous gray.

8. The male crossed is a heterozygous male (Gg), the male is gray.

III. Cross between a gray female, whose father was albino, with a heterozygous male (Gg X Gg):

We can make a good guess of the genotype of the female, given that gray color is dominant over albino, and the father was albino (gg). The father can only contribute sperm having only (g) allele, while the mother must contribute only a (G) allele to give a gray offspring. The gray female is definitely heterogyzous female i.e Gg

1. Probability of getting gray offspring (Gg or GG) =  ¾ (½ + ¼)  

2. Probability of getting albino offspring (gg) = ¼

3. There are 3 possible genotypes among the offspring, which are GG, Gg, and gg.

4. There are 2 possible phenotypes among the offspring, which are gray and albino coat color.

5. Probability of getting heterozygous offspring (i.e. Gg) = 2/4 = ½  

6. Probability of getting homozygous offspring (i.e. GG or gg) = Probability of getting GG + Probability of getting gg = ¼ + ¼ = ½  

7. The genotype of the female is Gg. We know this because we were given that it is gray in color, and gray is dominant over albino. Also, given that the father was albino (gg), a (g) allele can only be contributed by the father to combine with the dominant (G) allele to give us a female that has heterozygous gray coat color (Gg).

8. The genotype of the male is Gg. We know this because we were given that it was a heterozygous male. If an organism is heterozygous, it has different alleles controlling that trait.

IV. Cross between an albino female, whose father was gray, with a gray male, whose mother was albino (gg X Gg):

The albino female’s genotype is gg, because the g allele is recessive. The gray male’s genotype, whose mother was albino (gg) is definitely Gg, because gray is dominant, and to get a gray offspring, a G allele from the mother of the male must combine with the g allele that the albino father can only contribute i.e. Gg or GG from mother X gg from father = Gg (the gray male offspring).

1. Probability of getting gray offspring =  ¼ + ¼ = ½  

2. Probability of getting albino offspring (gg) = ¼ + ¼ = ½  

3. There are 2 possible genotypes among the offspring, which are Gg, and gg.

4. There are 2 possible phenotypes among the offspring, which are gray and albino coat color.

5. Probability of getting heterozygous offspring (i.e. Gg) = ¼ + ¼  = ½  

6. Probability of getting homozygous offspring (i.e. gg or GG) = ½ + 0 = ½  

7. The genotype of the gray father of the albino female (gg) is Gg. Of the two possible genotypes of the gray father (i.e. GG or Gg), Gg is the most likely genotype to contribute the recessive g allele that would pair up with another g allele from the mother to give an albino female (gg), i.e. Gg (father) X Gg (Mother) or Gg (Father) X gg (Mother) = gg (albino female)

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Which of these can be predicted with the help of science? meaning of life success in career severe weather conditions number of
Oxana [17]
"severe weather conditions" are the only things than can be reasonably well predicted with the help of science. Of course the accuracy of these predictions varies greatly. 
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