Just remember if it says incomplete u use the ‘ and only change the subscript for each characteristic ( brown hair, black hair, blonde hair)
Answer:
For example, the typical body colour phenotype is grey. One mutant produces an ebony (shiny black) body colour. Because this allele is recessive, it is symbolized by a lower-case letter, e.
Explanation:
Answer:
Post translation farnesylation may be defined as a type of prenylation in which the isoprenyl group is added to the cysteine residues of the protein. This modification is important for protein and membrane interaction.
Basically two types of amino acid are required for the farsenylation modification. The signal peptide sequence is the short amino acid sequence that targets the ribosome in the endoplasmic reticulum. The sequence is generally lysine, aspartic acid, glutamic acid and leucine. The second sequence must be Caax (C is cysteine, a is aliphatic amino acid and X consists of C terminal amino acid.
Answer:
<u>Part A</u> : 70 secondary oocytes will be formed.
<u>Part B</u> : 70 first polar bodies will be formed.
<u>Part C</u> : 70 ootids will be formed.
Explanation:
During oogenesis growth maturation of a single oogonium produces one primary oogonium.
the primary oogonium then undergoes meiosis -1 and produces one secondary oocyte and first polar body.
The secondary oocyte then undergoes meiosis - 2 and forms an ootid and second polar body.
The ootid then differentiates into the ovum.
As in the above scenario , 70 primary oocytes are present , they undergo meiosis-1 and produces 70 secondary oocytes and 70 first polar bodies. Hence answers of part A and B is 70.
As 70 secondary oocytes are formed , they undergo meiosis -2 and forms 70 ootids which then differentiate in 70 ovums.
