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oksano4ka [1.4K]
3 years ago
8

Find the diameter of a circle with an area of95.03 square feet.​

Mathematics
2 answers:
ra1l [238]3 years ago
7 0

For this case we have that the area of a circle is given by:

A = \pi * r ^ 2

Where:

r: It is the radius of the circle

By clearing the radio we have:

r = \pm \sqrt {\frac {A} {\pi}}

We take the positive value:

r = \sqrt {\frac {A} {\pi}}\\r = \sqrt {\frac {95.03} {\pi}}\\r = 5.50 \ ft

The diameter is twice the radius:

d = 11

Answer:

11 \ ft

Ivan3 years ago
7 0

<u>Answer:</u>

11 feet

<u>Step-by-step explanation:</u>

We are given the area of a circle and we are to find the diameter of this circle.

We know that the area of a circle is given by \pi r^2 so equating its given value to get:

\pi \times r^2 = 95.03

r ^ 2 = \frac {95.03} {\pi } r = \sqrt {30.25}

r = 5 . 5

Therefore, our required diameter will be 5.5 \times 2 = 11 feet

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1948 Olympics
mash [69]

Answer:

For 1948 Men's :Interquartile range is 1.5, Median is 58.3

For 2012 Men's: Interquartile range is 0.315, Median is 47.86

You can infer that in 2012 the swimmers were better and it was more competitive as the interquartile range was lower and the median was also lower as well

Step-by-step explanation:

1948 Men's 100m

57.3, 57.8, 58.1, 58.3, 58.3, 59.3, 59.6,1:00.5

               ⬆                ⬆                 ⬆

         Low IQR      Median       High IQR

Low IQR is average of 57.8 and 58.1 = 57.95

High IQR  is average of 59.3 and 59.6 =  59.45

Median is average of 58.3 and 58.3 = 58.3

Interquartile range is High IQR- Low IQR

59.45 - 57.95=1.5

2012 Men's 100m

47.52, 47.53, 47.8, 47.84, 47.88, 47.92, 48.04, 48.44

                    ⬆                  ⬆                      ⬆

             Low IQR         Median          High IQR

Low IQR is average of 47.53 and 47.8 = 47.665

High IQR is average of 48.04 and 47.92 = 47.98

Median is average of 47.88 and 47.84 = 47.86

Interquartile range is High IQR-Low IQR

47.98-47.665=0.315

Read more on Brainly.com - brainly.com/question/14915771#readmore

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The dimensions in inches of a shipping box at we ship 4 you can be expressed as width x, length x+5, and height 3x-1. The volume
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Step-by-step explanation:

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