Answer:
A. 2.3 sec and 5 sec
Step-by-step explanation:
We are given that start from 110 feet away, a person on a bicycle rides towards a checkpoint and then it passes it. the rider is traveling at a constant rate of 30 feet per second.
The distance between the bicycle and the checkpoint is given by the equation :
Now we are required to calculate at what times is the bike 40 feet away from the checkpoint. So, substitute d = 40 in the equation
and
and
and
and
and
Hence at 2.3 sec and 5 sec the bike is 40 feet away from the checkpoint.