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Alexxandr [17]
4 years ago
7

You estimate that you sent 135 texts last week but when you get the bill, it was actually 175. Calculate the percent error

Chemistry
1 answer:
FinnZ [79.3K]4 years ago
6 0

Answer: -40

Explanation: Percent error is calculated by subtracting the value you actually recieved from the literature value (175 in your case)  SO your answer should be 135-175=-40.

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The activation energy of a certain uncatalyzed biochemical reaction is 50.0 kJ/mol. In the presence of a catalyst at 37°C, the r
rodikova [14]

Answer:

E₁ ≅ 28.96 kJ/mol

Explanation:

Given that:

The activation energy of a certain uncatalyzed biochemical reaction is 50.0 kJ/mol,

Let the activation energy for a catalyzed biochemical reaction = E₁

E₁ = ??? (unknown)

Let the activation energy for an uncatalyzed biochemical reaction = E₂

E₂ = 50.0 kJ/mol

    = 50,000 J/mol

Temperature (T) = 37°C

= (37+273.15)K

= 310.15K

Rate constant (R) = 8.314 J/mol/k

Also, let the constant rate for the catalyzed biochemical reaction = K₁

let the constant rate for the uncatalyzed biochemical reaction = K₂

If the  rate constant for the reaction increases by a factor of 3.50 × 10³ as compared with the uncatalyzed reaction, That implies that:

K₁ = 3.50 × 10³

K₂ = 1

Now, to calculate the activation energy for the catalyzed reaction going by the following above parameter;

we can use the formula for Arrhenius equation;

K=Ae^{\frac{-E}{RT}}

If K_1=Ae^{\frac{-E_1}{RT}} -------equation 1     &

K_2=Ae^{\frac{-E_2}{RT}} -------equation 2

\frac{K_1}{K_2} = e^{\frac{-E_1-E_2}{RT}

E_1= E_2-RT*In(\frac{K_1}{K_2})

E_1= 50,000-8.314*310.15*In(\frac{3.50*10^3}{1})

E_1 = 28957.39292  J/mol

E₁ ≅ 28.96 kJ/mol

∴ the activation energy for a catalyzed biochemical reaction (E₁) = 28.96 kJ/mol

8 0
3 years ago
Which type of energy refers to the sum of potential and kinetic energies in the particles of a substance?
Andru [333]

Thermal (heat) energy is ur answer mate

Hope it helps

5 0
4 years ago
All-sized companies are required to have a written fire prevention plan.
dlinn [17]

Answer: i say yes

and the information i got why is down below that way you can see if im right if you dont trust me

What OSHA standards require a fire prevention plan?

A fire prevention plan must be in writing, be kept in the workplace, and be made available to employees for review. However, an employer with 10 or fewer employees may communicate the plan orally to employees. The name or job title of employees responsible for the control of fuel source hazards.

Explanation:

While OSHA strongly recommends that all employers have an FPP, you are only required to have a fire prevention plan when an applicable OSHA standard requires it. Those standards include: Ethylene oxide, §1910.1047. Methylenedianiline, §1910.1050.

7 0
3 years ago
Read 2 more answers
I don’t need the answers to this but u can if u want but I’m just asking what is this is asking for and how to solve it? I hope
strojnjashka [21]

Answer:

See explanation

Explanation:

Salts are produced from the reaction of an acid and a base. In general ...

Acid + Base => Salt + Weak Electrolyte

Acids from the 'Arrhenius Definition' contain an 'ionizable' hydrogen (-H). Such as, HCl, HBr, HI, HNO₃, HClO₄, HF, etc.

Bases from the 'Arrhenius Definition' contain an 'ionizable' hydroxide (-OH). Such as, LiOH, NaOH, KOH, CsOH, Ca(OH)₂, etc.

When the acid and base react, they proceed by what is known as a 'Double Replacement Reaction' or 'Metathesis Reaction'. In the process, the ions of the reactant compounds exchange positions such that a 'Driving Force' compound is formed on the product side. The Driving Force compound is <u>always</u> on the product side of the equation and is a compound that takes one of three forms => A precipitating salt, a compound of a weak acid or weak base (weaker than the starting acid or base) or gas decomposition product (~ vinegar + backing soda rxn => CO₂ gas).

For your problem, split the compound into cations and anions. You can usually tell which is which by using this format on formulas like those listed in your question => reading formula from left to right, place an imaginary line after the 1st metal => this metal will be the cation & the remaining formula will be the anion.

KBr => K | Br => K (Potassium) is the cation (K⁺) and Br (Bromide) is the anion (Br⁻)

KBr => K⁺ + Br⁻

Now. Apply this rule => Add 'H' to anion => HBr,  then add 'OH' to cation => KOH.

HBr is the acid and KOH is the base. Therefore ...        

Acid + Base => Salt + Wk Electrolyte

HBr + KOH => KBr + H₂O (note how ions of reactants exchange places to form products).

So, KBr comes from the reaction of acid HBr and base KOH.

HBr + KOH => KBr + H₂O

To determine the acid and base origins of LiCl and NaF, use the same logic. Hope this helps. Doc :-)

7 0
3 years ago
How many atoms of neon (Ne) are in a 1452.96 moles sample of neon?
Firlakuza [10]

Answer:

8749.73× 10²³ atoms of He

Explanation:

Given data:

Number of atoms of neon = ?

Number of moles of neon = 1452.96 mol

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

1452.96 mol ×  6.022 × 10²³ atoms of He/ 1 mol

8749.73× 10²³ atoms of He

7 0
4 years ago
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