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kow [346]
3 years ago
12

Solid aluminum is placed in a beaker with a blue solution of copper(II) nitrate. The resulting reaction causes the blue solution

to turn colorless. The solid aluminum is consumed while a spongy, dark brown solid forms. Based on the observations listed above, which of the following inference(s) would be valid?
A. A synthesis reaction occurred.
B. A single replacement reaction occurred.
C. A double replacement reaction occurred.
D. A redox reaction occurred.
Chemistry
1 answer:
konstantin123 [22]3 years ago
7 0

Answer:

Option D. A redox reaction occurred.

Explanation:

From the question given above it evident that a redox reaction has occurred because there is a colour change when aluminum was introduced into the beaker containing blue solution of copper(II) nitrate.

The equation for the reaction is given below below:

2Al + 3Cu(NO3)2 —> 2Al(NO3)3 + 3Cu

The oxidation number of Al changes from 0 to +2 indicating oxidation and the oxidation number of Cu changes from +2 to 0 indicating reduction.

As the oxidation - reduction reaction occurs, a colour change is observed.

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Answer:

True

Explanation:

A magnetic field is made when an electric current flows through a wire.

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Which term describes the maintenance of a steady internal state in the body?
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Dalton's law of partial pressures states that the total pressure exerted by a mixture of gases is the sum of the pressures exert
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Answer: The given statement is true.

Explanation:

According to the Dalton's law, total pressure of a mixture of gases that do not react with each other is equal to the partial pressure exerted by each gas.

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          p_{total} = \sum_{i=1}^{n} p_{i}

or,        p_{total} = p_{1} + p_{2} + p_{3} + p_{4} + ......... + p_{n}

where,  p_{1}, p_{2}, p_{3} ....... = partial pressure of individual gases present in the mixture

Also, relation between partial pressure and mole fraction is as follows.

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where,      x_{i} = mole fraction

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in heating a kettle of water on an electric stove, 3.34×10^3 J of thermal energy was provided by the element of the stove. yet,
insens350 [35]

Answer:

The percentage efficiency of the electrical element is approximately 82.186%

Explanation:

The given parameters are;

The thermal energy provided by the stove element, H_{supplied} = 3.34 × 10³ J

The amount thermal energy gained by the kettle, H_{absorbed}  = 5.95 × 10² J

The percentage efficiency of the electrical element in heating the kettle of water, η%, is given as follows;

\eta \% = \dfrac{H_{supplied} - H_{absorbed} }{H_{supplied}}  \times 100

Therefore, we get;

\eta \% = \dfrac{3.34 \times 10^3 - 5.95 \times 10^2}{3.34 \times 10^3}  \times 100 = \dfrac{549}{668} \times 100 \approx 82.186 \%

The percentage efficiency of the electrical element, η% ≈ 82.186%.

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