Q = mCpΔT —> Solve for Cp —> Cp = q/mΔT
q = -6700 J (negative because it released heat
m = 70 g
ΔT = Final temp - initial temp = 25 - 90 = -65°C
Cp = -6700 J / (70 g)(-65°C) = 1.47 J/g°C
The mass of carbon dioxide that would be produced will be 22 kg
<h3>Combustion of carbon</h3>
The combustion of carbon in air can be represented by the equation:
C + O2 ---> CO2
The mole ratio of C to O2 to CO2 is 1:1:1.
Mole of 6kg of carbon = mass/molar mass
= 6000/12
= 500 moles
Equivalent mole of CO2 produced = 500 moles
Mass of 500 moles CO2 = mole x molar mass
= 500 x 44.01
= 22,005 g or 22 kg approximately
More on combustion reactions can be found here: brainly.com/question/13649083
The presence of H3O+ is the hydronium ion, and one definition of an acid is something that donates a proton (H+). HCl in this case does just that. Basic solution forming with NaOH and water: ... NaOH + H2O ==>Na+ + OH- so it donates or produces OH- ions, thus making a basic solution
Answer:
false should be the correct response.