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kow [346]
4 years ago
12

Solid aluminum is placed in a beaker with a blue solution of copper(II) nitrate. The resulting reaction causes the blue solution

to turn colorless. The solid aluminum is consumed while a spongy, dark brown solid forms. Based on the observations listed above, which of the following inference(s) would be valid?
A. A synthesis reaction occurred.
B. A single replacement reaction occurred.
C. A double replacement reaction occurred.
D. A redox reaction occurred.
Chemistry
1 answer:
konstantin123 [22]4 years ago
7 0

Answer:

Option D. A redox reaction occurred.

Explanation:

From the question given above it evident that a redox reaction has occurred because there is a colour change when aluminum was introduced into the beaker containing blue solution of copper(II) nitrate.

The equation for the reaction is given below below:

2Al + 3Cu(NO3)2 —> 2Al(NO3)3 + 3Cu

The oxidation number of Al changes from 0 to +2 indicating oxidation and the oxidation number of Cu changes from +2 to 0 indicating reduction.

As the oxidation - reduction reaction occurs, a colour change is observed.

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Alkaline earth metal are the elements present in II group in the periodic table and are known as 'Metals' and have a charge of +2.

Alkaline earth metals - Be , Mg Ca, Sr , Ba, Ra

Halogens are present in VII A group in the periodic table and are 'Non-metals' and have a charge of -1.

Halogens - F, Cl, Br, I, At

When Alkaline earth metal (metals) combine with Halogens (non-metals) the compound formed will be ionic compound and the formula of the compound will be based on the charges of the element.

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For example - Mg (Alkaline earth metal) have a charge of +2 and Cl (Halogen) have a charge of -1 and when they combine to form the formula their charges get criss crossed and we will get Mg_{1}Cl_{2} or MgCl_{2}

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4 years ago
Let us assume that cu(oh)2(s) is completely insoluble, which signifies that the precipitation reaction with naoh(aq) (presented
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4 years ago
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