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stich3 [128]
4 years ago
8

What is the Ka of a 0.0796 M solution of nitrous acid (HNO2) with a pH of 2.95?

Chemistry
1 answer:
Vadim26 [7]4 years ago
4 0

Answer:

Coefficient = 1.58

Exponent = - 5

Explanation:

pH = 2.95

Molar concentration = 0.0796M

Ka = [H+]^2 / [HA]

Ka = [H+]^2 / 0.0796

Therefore ;

[H+] = 10^-2.95

[H+] = 0.0011220 = 1.122 × 10^-3

Ka = [H+] / molar concentration

Ka = [1.122 × 10^-3]^2 / 0.0796

Ka = (1.258884 × 10^-6) / 0.0796

Ka = 15.815 × 10^-6

Ka = 1.58 × 10^-5

Coefficient = 1.58

Exponent = - 5

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An aqueous solution of potassium carbonate combine with a solution of calcium nitrate. What are the total and net ionic equation
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<span><span>K_2</span>C<span>O_3</span>(aq)+Ca(N<span>O_3</span><span>)_2</span>(aq)→ ?</span>
If we break these two reactants up into their respective ions, we get...<span><span>
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If we combine the anion of one reactant with the cation of the other and vice-versa, we get...<span>
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Now we need to ask ourselves if either of these is soluble in water. Based on solubility rules, we know that all nitrates are soluble, so the potassium nitrate is. Alternatively, we know that all carbonates are insoluble except those of sodium, potassium, and ammonium; therefore, this calcium carbonate is insoluble. This is good. It means we have a driving force for the reaction! That driving force is that a precipitate will form. In such a case, a precipitation reaction will occur, and the total equation will be...<span><span>
K_2</span>C<span>O_3</span>(aq) + Ca(N<span>O_3</span><span>)_2</span>(aq) → CaC<span>O_3</span>(s) + 2KN<span>O_3</span>(aq)</span>

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5 0
3 years ago
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Dima020 [189]

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<h3>What is Entropy ?</h3>

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Now lets check all options one by one

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So it is correct option

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Hence, Option (D) is correct answer.

Learn more about the Entropy here: brainly.com/question/1477087

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