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2 years ago

11

In forming a molecular compound, each atom should have ______ electrons around it unless there is some specific reasons why this

cannot be achieved.

1 answer:

ivolga24 [154]2 years ago

5 0

In forming a molecular compound, each atom should have <u>valence</u> electrons around it unless there is some specific reasons why this cannot be achieved.

<h3>What is Valence Electrons ?</h3>

Valence electrons is a negatively charged particle present in the outermost shell of an atom.

Example: Oxygen has 6 valence electrons in its outermost shell, Water has 8 valence electrons.

Thus from the above conclusion we can say that In forming a molecular compound, each atom should have <u>valence</u> electrons around it unless there is some specific reasons why this cannot be achieved.

Learn more about the Valence Electrons here: brainly.com/question/371590

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011 1.0 points What energy change is associated with the reaction to obtain one mole of H2 from one wang (ew22622) – 19D Thermod

vlada-n [284]

Answer:

<em>249 kJ</em>

Explanation:

To obtain the energy change of the reaction:

H₂O → H₂ + ¹/₂ O₂

It is necessary to obtain the difference between bond energy of the products and bond energy of the reactant, thus:

Energy of products:

1 mol of H-H bond × 436 kJ/mol = 436 kJ

¹/₂ mol of O=O bond × 498 kJ/mol = 249 kJ

Energy of reactant:

2 mol of H-O bond × 467 kJ/mol = 934 kJ

Energy change of the reaction is:

934 kJ - (436 kJ + 249 kJ) = <em>249 kJ</em>

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I hope it helps!

4 0

3 years ago

What causes each new row of the periodic table

taurus [48]

Answer:

elements have the same number of valence electrons and similar chemical properties.

Explanation:

they have the same number

8 0

3 years ago

Between Lab Period 1 and Lab Period 2, design a separation scheme for all 4 cations. Use the results of your preliminary tests a

fiasKO [112]

Answer:

SEPARATION SCHEME FOR CATIONS

GIVEN CATIONS : $Ag^{+} \ , Fe^{3+} , Cu^{2+}, Ni^{2+}$

Step 1: Add $6mol/dm^3$ of $HCl$ to the mixture solution

Result : This would cause a precipitate of $AgCl$ to be formed

Reaction : $Ag^{+} _{(aq)} + Cl^{-} _{(aq)} ---------> AgCl(ppt)$

Step 2 : Next is to remove the precipitate and add $H_2S$ to the remaining

solution in the presence of $0.2 \ mol/dm^3$ of HCl

Result : This would cause a precipitate of $CuS$ to be formed

Reaction : $Cu^{2+}_{(aq)} + S^{2-}_{(aq)} ------> Cu_2S(ppt)$

Step 3: Next remove the precipitate then add $6 \ mol/dm^3$ of aqueous

$NH_3 (NH_3 \cdot H_2 O)$ , process the solution in a centrifuge,when the

process is done then sort out the precipitate from the solution

Now this precipitate is $Fe(OH)_3$ and the remaining solution

contains $(Ni (NH_3)_6)$

Next take out the precipitate to a different beaker and add HCl

to it this will dissolve it, then add a drop of $NH_4SCN$ this will

form a precipitate $Fe(SCN)_{6}^{3-}$ which will have the color of

blood indicating the presence of $Fe^{3+}$

Reaction : $F^{3+}_{(aq)} + 30H^-_{(aq)} --------->Fe(OH)_3_{(aq)}$

$Fe (OH)_{(s)} _3 + 3H^{+}_{aq} -------> Fe^{3+}_{aq} + 3H_2O_{(l)}$

$Fe^{3+} + 6SCN^{-} -----> Fe(SCN)_6 ^{3-}$

Now the remaining mixture contains $Ni^{2+}$

Explanation:

6 0

3 years ago

What volume of a 0.580-m solution of cacl2 contains 1.28 g solute?

goldfiish [28.3K]

Answer : 19.9 mL

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Now, we can find out the volume from this;

0.01153 mol X (1 L / 0.580 mol) X (1000 mL / 1 L) = 19.9 mL

Hence, the volume will be 19.9 mL

7 0

3 years ago

Which element is NOT in the cobalt subgroup? <br> a)iron <br> b)cobalt <br> c)iridium <br> d)rhodium

hoa [83]

Iron is the element that is not in the cobalt subgroup.

8 0

3 years ago

Read 2 more answers