Answer is: <span>A. 18.02 g/mol.
At standard temperature and pressure 1 mol of gas occupied 22.4 liters:
V(H</span>₂O) = 22.4 L; volume of water.
Vm = 22.4 L/mol; molar volume at STP.
n(H₂O) = V ÷ Vm.
n(H₂O) = 22.4 L ÷ 22.4 L/mol.
n(H₂O) = 1 mol; amount of substance (water).
M(H₂O) = Ar(O) + 2Ar(H) · g/mol.
M(H₂O) = 16 + 2 ·1.01 · g/mol.
M(H₂O) = 18.02 g/mol; molar mass of water.
Answer:
8.9L is the volume of the gas that must be dissolved.
Explanation:
For a weak base, we can find [(CH₃)₃N] using the equation:
Kb = [OH⁻] [[(CH₃)₃NH⁺] / [(CH₃)₃N]
As [OH⁻] = [[(CH₃)₃NH⁺] and [OH⁻] = 10^-pOH = 3.16x10⁻³M:
6.3x10⁻⁵ = [3.16x10⁻³M][3.16x10⁻³M] / [(CH₃)₃N]
[(CH₃)₃N] = 0.1587M
As the volume is 2.5L, moles are:
2.5L * (0.1587mol / L) = 0.3968moles
Using:
PV = nRT
We can solve for volume of the gas as follows:
P = 1atm at STP; n = 0.3968moles; R = 0.082atmL/molK; T = 273.15K at STP
V = 0.3968mol*0.082atmL/molK*273.15K/1atm
V = 8.9L is the volume of the gas that must be dissolved.
Answer:a law stating that the volume of an ideal gas at constant pressure is directly proportional to the absolute temperature
Explanation:
Explanation:
According to the Bronsted-Lowry conjugate acid-base theory:
- An acid is defined as a substance which looses donates protons and thus forming conjugate base
- A base is defined as a substance which accepts protons and thus forming conjugate acid.

Suppose acid Ha is getting dissociated in its solution and after dissociation it donates its proton to water molecule and forms conjugate base. Where as water (acting as a base) accepts protons and forms conjugate acid.
HA = Acid
= Base
= Conjugate base
= Conjugate acid
For example:

Sulfuric acid dissociating in its solution to form conjugate base and conjugate acid.
Sulfuric acid = Acid
= Base
= Conjugate base
= Conjugate acid