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just olya [345]
3 years ago
6

64 ft of rope weighs 20 pounds 28 ft of rope weighs x pounds​

Mathematics
1 answer:
castortr0y [4]3 years ago
4 0

Answer

89.6

Step-by-step explanation:

Each foot of rope weighs 3.2 so then mutiplied 3.2 by 28 and got that

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Its super duper easy but im having some trouble<br> so can someone help me?
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together = add

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3 7/10 + 5 9/10

add the whole numbers first

3+5=8

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16/2= 8

10/2= 5

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9 3/5

Answer:

9 3/5

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What is easy-access credit?
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Step-by-step explanation:

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3 years ago
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It depends on how many options you have
You multiply the total number of books you have time 5 because you can choose 5
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3 years ago
Lilith and her friend shared a pizza. Lilith ate two sixths of the pizza and her friend ate three sixths. How much pizza did the
Tcecarenko [31]

Step-by-step explanation:

\frac{2}{6}  +  \frac{3}{6 }  =

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6 0
1 year ago
Suppose that the population mean for income is $50,000, while the population standard deviation is 25,000. If we select a random
Fudgin [204]

Answer:

Probability that the sample will have a mean that is greater than $52,000 is 0.0057.

Step-by-step explanation:

We are given that the population mean for income is $50,000, while the population standard deviation is 25,000.

We select a random sample of 1,000 people.

<em>Let </em>\bar X<em> = sample mean</em>

The z-score probability distribution for sample mean is given by;

               Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean = $50,000

            \sigma = population standard deviation = $25,000

            n = sample of people = 1,000

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the sample will have a mean that is greater than $52,000 is given by = P(\bar X > $52,000)

  P(\bar X > $52,000) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{52,000-50,000}{\frac{25,000}{\sqrt{1,000} } } ) = P(Z > 2.53) = 1 - P(Z \leq 2.53)

                                                                    = 1 - 0.9943 = 0.0057

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2.53 in the z table which has an area of 0.9943.</em>

Therefore, probability that the sample will have a mean that is greater than $52,000 is 0.0057.

5 0
2 years ago
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