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TiliK225 [7]
2 years ago
10

Plz plz help im not good at math..................................at all

Mathematics
1 answer:
asambeis [7]2 years ago
6 0

Answer:

8: subtract 1.50 from 11.50 until you get to 7.00 and count how many times you subtracted it that is your answer

9: take 254 and subtract 4 until you get to 228 count how many times you subtracted and that is your answer

10: take ten and add 6 until you get to 46 count how many times you added and that is your answer

Step-by-step explanation:

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Does anyone know the answer for the question below.
vaieri [72.5K]

let's take the postive value for a while (that is the value in first quadrant.)

\tan(x) =\frac{\text{perpendicular or opposite side}}{\text{base or adjacent side}} \\ \tan(x)=2 \\  \text{if you imagine a triangle with perpendicular =2 and base =1, and use Pythagoras theorem, you will get hypotenuse} \\ h^2= 2^2+1^2 \\ h^2=4+1 =5 \\ h=\sqrt5 \\ \cos(x)=\frac{\text{base or adjacent side}}{\text{hypotenuse}} \\ \cos(x)=\frac{1}{\sqrt5} \\ \text{ since x is in second quadrant, where both tangent and cosine are negative, just add a negative sign} \\ \cos(x)= -\frac{1}{\sqrt5}

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3 years ago
Please help me with the first question!
Vsevolod [243]

\qquad \qquad  \bf \huge\star \:  \:  \large{  \underline{Answer} }  \huge \:  \: \star

\qquad❖ \:  \sf   \: \angle C  = 63 \degree

\textsf{  \underline{\underline{Steps to solve the problem} }:}

\qquad❖ \:  \sf \:x + 4x  + 12 + x=180°

( Angle EBA= Angle DBC, and the three angles sum upto 180° due to linear pair property )

\qquad❖ \:  \sf \:6x + 12 = 180

\qquad❖ \:  \sf \:6x = 180 - 12

\qquad❖ \:  \sf \:6x = 168

\qquad❖ \:  \sf \:x = 28 \degree

Next,

\qquad❖ \:  \sf   \: \angle C + \angle D + x = 180°

\qquad❖ \:  \sf   \: \angle C +3x + 5  + x = 180°

\qquad❖ \:  \sf   \: \angle C +4x  = 180 - 5

\qquad❖ \:  \sf   \: \angle C +4(28)  = 175

( x = 28° )

\qquad❖ \:  \sf   \: \angle C +112  = 175

\qquad❖ \:  \sf   \: \angle C  = 175 - 112

\qquad❖ \:  \sf   \: \angle C  = 63 \degree

\qquad \large \sf {Conclusion}  :

\qquad❖ \:  \sf   \: \angle C  = 63 \degree

4 0
1 year ago
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