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Amiraneli [1.4K]
3 years ago
9

Solving a motion problem using a system of equations

Mathematics
1 answer:
kvasek [131]3 years ago
8 0
Step 1 understand the problem make sure that you read the questions carefully several times Step 2 devise a plan Translate step 3 carry out the plan solve this is a system of linear equations with 3 variables
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PLEASE HELPP NOW!!!!!
BaLLatris [955]

Answer:

the codrect answer is 625

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2 years ago
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What is the slope of the line?
Strike441 [17]
The slope of the line is 1
7 0
3 years ago
A data set contains information on the grams of fat and number of calories in 28 different fast foods. The correlation coefficie
k0ka [10]

Using a calculator, it is found that for the two-tailed test of significance, the p-value is of 0.9195.

The correlation coefficient is also called <u>Pearson's r-score</u>, and is used for two-tailed tests. To find the p-value, the information needed is:

  • The value of the Pearson's r-score, that is, the value of the correlation coefficients.
  • The sample size.

In this problem, we have that the correlation coefficient is of r = 0.02, with a sample size of n = 28.

  • Using it as the input for a r-score calculator, the p-value is of 0.9195.

A similar problem is given at brainly.com/question/13873630

6 0
2 years ago
Same this for me but 6,912 and 288 please help
Svetllana [295]

Answer:

what is the question

Step-by-step explanation:

Questions for answers

4 0
3 years ago
Would appreciate some help with this:<br><br> Verify (sinq+cosq)^2 - 1 = sin2q
Phantasy [73]

Hello from MrBillDoesMath!

Answer:

See Discussion below

Discussion:

(sinq + cosq)^2 =                                     => (a +b)^2 = a^2 + 2ab + b^2

(sinq)^2 + (cosq)^2 + 2 sinq* cosq        => as (sinx)^2 + (cosx)^2 = 1

1 + 2 sinq*cosq              (*)


Setting a = b = q in the trig identity:

sin(a+b) = sina*cosb + cosa*sinb                      

sin(2q) =                      (**)

sinq*cosq + cosq*sinq      => as both terms are identical

2 sinq*cosq


Combining (*) and (**)

(sinq + cosq)^2 = 1 + 2sinq*cosq     => (**) 2sinq*cosq =  sqin(2q)

                          = 1 +  sin(2q)

Hence

(sinq + cosq)^2  = 1 +  sin(2q)            => subtracting 1 from both sides

(sinq + cosq)^2  - 1 =   sin(2q)  

The last statement is what we are trying to prove.



Thank you,

MrB

7 0
3 years ago
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