1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Luda [366]
3 years ago
7

Identify the control group and the independent and dependent variables in the following scenario: 300 chickens are divided into

three equal sized groups. Group A is injected weekly with 10 mg of a growth hormone. Group B is injected weekly with 25 mg of the growth hormone. Group C is not given any growth hormone. All 300 chickens are weighed after again after 3 months.
Chemistry
2 answers:
timama [110]3 years ago
8 0

Answer:

the control group is group c

independent variable - number of mg of growth hormone

dependent variable - growth of chickens

Explanation:

the control has nothing added to it

the growth of chickens DEPEND on the growth hormome :)

Olenka [21]3 years ago
4 0

Answer:

I saw your question 4 months ago about Overwatch

Explanation:

Im down to play bro lol  , I play on pc aswell

hmu, my dis cord is Conspiracy#2546  and btag is Conspiracy#11218

You might be interested in
A detrital rock is named according to ____.
netineya [11]
I believe the answer is D.
5 0
3 years ago
How many moles are in 39.5 grams of Lithium?
Blizzard [7]

Answer:

185.05 g.

Explanation

Firstly, It is considered as a stichiometry problem.

From the balanced equation: 2LiCl → 2Li + Cl₂

It is clear that the stichiometry shows that 2.0 moles of LiCl is decomposed to give 2.0 moles of Li metal and 1.0 moles of Cl₂, which means that the molar ratio of LiCl : Li is (1.0 : 1.0) ratio.

We must convert the grams of Li metal (30.3 g) to moles (n = mass/atomic mass), atomic mass of Li = 6.941 g/mole.

n = (30.3 g) / (6.941 g/mole) = 4.365 moles.

Now, we can get the number of moles of LiCl that is needed to produce 4.365 moles of Li metal.

Using cross multiplication:

2.0 moles of LiCl → 2.0 moles of Li, from the stichiometry of the balanced equation.

??? moles of LiCl → 4.365  moles of Li.

The number of moles of LiCl that will produce 4.365 moles of Li (30.3 g) is (2.0 x 4.365 / 2.0) = 4.365 moles.

Finally, we should convert the number of moles of LiCl into grams (n = mass/molar mass).

Molar mass of LiCl = 42.394 g/mole.

mass = n x molar mass = (4.365 x 42.394) = 185.05 g.

7 0
3 years ago
Read 2 more answers
What is the expected ionic charge when group VI elements participate in ionic bonds?
valina [46]
Group 6 elements usually have extra electrons to make give them an octet. So, they have 6 electrons to start and when they have an octet, they have 8.

We can find the charge by doing simple math 6 - 8 = -2

Answer is D)
3 0
4 years ago
A balloon has an initial volume of 2.954 L containing 5.50 moles of helium. More helium is added so that the balloon expands to
Luda [366]

Answer:

8.05 moles

Explanation:

5.50 / 2.954 = x / 4.325

x = 8.05

6 0
3 years ago
How many kilojoules of energy would be required to heat a 225g block of aluminum from 23.0 C to 73.5 C?
gulaghasi [49]

Answer:

\boxed {\boxed {\sf 10.2 \ kJ}}

Explanation:

We are asked to find how many kilojoules of energy would be required to heat a block of aluminum.

We will use the following formula to calculate heat energy.

q=mc \Delta T

The mass (m) of the aluminum block is 225 grams and the specific heat (c) is 0.897 Joules per gram degree Celsius. The change in temperature (ΔT) is the difference between the final temperature and the initial temperature.

  • ΔT = final temperature - inital temperature

The aluminum block was heated from 23.0 °C to 73.5 °C.

  • ΔT= 73.5 °C - 23.0 °C = 50.5 °C

Now we know all three variables and can substitute them into the formula.

  • m= 225 g
  • c= 0.897 J/g° C
  • ΔT= 50.5 °C

q= (225 \ g )(0.897 \ J/g \textdegree C)(50.5 \textdegree C)

Multiply the first two numbers. The units of grams cancel.

q= (225 \ g  * 0.897 \ J/g \textdegree C)(50.5 \textdegree C)

q= (225   * 0.897 \ J / \textdegree C)(50.5 \textdegree C)

q= (201.825\ J / \textdegree C)(50.5 \textdegree C)

Multiply again. This time, the units of degrees Celsius cancel.

q= 201.825 \ J * 50.5

q= 10192.1625 \ J

The answer asks for the energy in kilojoules, so we must convert our answer. Remember that 1 kilojoule contains 1000 joules.

\frac { 1  \ kJ}{ 1000 \ J}

Multiply by the answer we found in Joules.

10192.1625 \ J * \frac{ 1 \ kJ}{ 1000 \ J}

10192.1625  * \frac{ 1 \ kJ}{ 1000 }

\frac {10192. 1625}{1000} \ kJ

10.1921625 \ kJ

The original values of mass, temperature, and specific heat all have 3 significant figures, so our answer must have the same. For the number we found, that is the tneths place. The 9 in the hundredth place tells us to round the 1 up to a 2.

10.2 \ kJ

Approximately <u>10.2 kilojoules</u> of energy would be required.

3 0
3 years ago
Other questions:
  • 50 POINTS!!!!!
    13·1 answer
  • The more particles a substance has at a given temperature, the ___?
    11·2 answers
  • Differentiate between crystalline and amorphous solid.
    11·2 answers
  • Arrange the following aqueous solutions in order of decreasing freezing point. (The last three are all assumed to dissociate com
    15·1 answer
  • Elements donate 2 electron to produce a cation with a 2+ charge
    13·1 answer
  • I need help with that
    10·1 answer
  • What elements are the monomers of proteins made of?
    11·1 answer
  • How does modern periodic table explain the cause of periodicity. ​
    14·1 answer
  • What is the only nonmetal with four valence electrons?.
    11·1 answer
  • How much N2 is required to fill a small room with a volume of 27,000 L to a pressure of 0.82 atm at 25 °C?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!