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yaroslaw [1]
3 years ago
11

Differentiate between crystalline and amorphous solid.

Chemistry
2 answers:
Solnce55 [7]3 years ago
8 0

1) Amorphous means “without form or structure".

In amorphous solid atoms and molecules are not organized in a definite lattice pattern. For example plastic, gel or glass.

Crystal constituents (atoms, molecules or ions) are arranged in a highly ordered microscopic structure, forming a crystal lattice that extends in all directions.

2) Amorphous solids do not have definite melting points.

Crystalline solids have definitive melting point.

Anit [1.1K]3 years ago
4 0
<h2>DIFFERENCE BETWEEN CRYSTALLINE AND AMORPHOUS SOLIDS :</h2><h2><em><u> Amorphous solids do not have definite melting points but melt over a wide range of temperature because of the irregular shape. Crystalline solids, on the other hand, have a sharp melting point.</u></em></h2>
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Firlakuza [10]

Answer:

2.2mL

Explanation:

First, let us analyse what was given from the question:

C1 = 2.09M

V1 =?

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V2 =100mL

Using dilution formula (C1V1 = C2V2), we can calculate the volume of the original solution as follows:

C1V1 = C2V2

2.09 x V1 = 0.046 x 100

Divide both side by the coefficient of V1 ie 2.09, we have:

V1 = (0.046 x 100) / 2.09

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3 years ago
Which of the following is a balanced chemical equation? A, H2O2 → H2O + O2
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I believe it's D! Hope you can help with my question!
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Given the following information, what is the concentration of H2O(g) at equilibrium? [H2S](eq) = 0.671 M [O2](eq) = 0.587 M Kc =
MAVERICK [17]

<u>Answer:</u> The equilibrium concentration of water is 0.597 M

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For a general chemical reaction:

aA+bB\rightleftharpoons cC+dD

The expression for K_{eq} is written as:

K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

The concentration of pure solids and pure liquids are taken as 1 in the expression.

For the given chemical reaction:

2H_2S(g)+O_2(g)\rightleftharpoons 2S(s)+2H_2O(g)

The expression of K_c for above equation is:

K_c=\frac{[H_2O]^2}{[H_2S]^2\times [O_2]}

We are given:

[H_2S]_{eq}=0.671M

[O_2]_{eq}=0.587M

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Putting values in above expression, we get:

1.35=\frac{[H_2O]^2}{(0.671)^2\times 0.587}

[H_2O]=\sqrt{(1.35\times 0.671\times 0.671\times 0.587)}=0.597M

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8 0
3 years ago
How many grams of the excess reactant remain assuming the reaction goes to completion and that you start with 15.5g of na2s and
tangare [24]
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3 years ago
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Hope this helps
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3 years ago
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