|x + 2| + 16 = 1
<u> - 16 - 16</u>
|x + 2| = -15
x + 2 = -15 U x + 2 = 15
<u> - 2 - 2</u> <u> - 2 - 2</u>
x = -17 x = 13
|2x + 6| - 4 = 20
<u> + 4 + 4</u>
|2x + 6| = 24
2x + 6 = 24 U 2x + 6 = -24
<u> - 6 - 6</u> <u> - 6 - 6</u>
<u>2x</u> = <u>18</u> <u>2x</u> = <u>-30</u>
2 2 2 2
x = 9 x = -15
9x + 27
-2y + 20
4x - 24
30x + 12xy
15x + 2 (?)
~ I’m not sure abt the last one! I’m sorry if they’re incorrect and I hoped this helps! ~
Hope this is what you are looking for
Answer: j=t^2+5
Step-by-step explanation:
Answer:

Step-by-step explanation:
Relation between acceleration, velocity and position:
The velocity function is the integral of the acceleration function.
The position function is the integral of the velocity function.
Acceleration:
As given by the problem, the acceleration function is 
Velocity:

In which K is the constant of integration, which is the initial velocity. So K = -3 and:

Position:

In which K, the constant of integration, is the initial position. Since it is 12:
