Answer:
Given:
Sample size, n = 640
Since result showed that 99.2% of them would erase all of their personal information online if they could, we have:
P' = 99.2% = 0.992
Let's take p = 50%
Our null and alternative hypothesis will be :
H0 : u = 0.5
H1 : u > 0.5
In this case we are to check for the test statistic.


= 24.9
Test statistic, Z = 24.893
In conclusion, the results are significantly high, which suggets there is suffcient evidence to support the claim that most adults would erase all of their personal information online.
Answer:
Yes
Step-by-step explanation:
I honestly don’t know sorry
45th percentile means that 45% of the data fall below that number while 55% (that is, 100-45) fall above it.
Now, arranging the number in ascending order;
$60, $85, $95, $105, $120, $145, $155, $175, $190, $215, $235, $240, $260, $285, $325
The total number of counts = 15
Then,
Index = 15*45% = 15*0.45 = 6.75
Round up,
Index = 7
The,
7th number = $155
Therefore, 45th percentile value of the data = $155