Considering that the addresses of memory locations are specified in hexadecimal.
a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ ) = 65536 memory locations
b) The range of hex addresses in a microcomputer with 4096 memory locations is ; 4095
<u>applying the given data </u>:
a) first step : convert FFFF₁₆ to decimal ( note F₁₆ = 15 decimal )
( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )
= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )
= 61440 + 3840 + 240 + 15 = 65535
∴ the memory locations from 0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations
b) The range of hex addresses with a memory location of 4096
= 0000₁₆ to FFFF₁₆ = 0 to 4096
∴ the range = 4095
Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.
Learn more : brainly.com/question/18993173
36 1/2 to 37.
45.5 - 36 1/2 = 9
those would be the ones I'd click
V=4x-1 I believe is the anwsers
Answer:
and 
Step-by-step explanation:
Note that if 
then 
Functions 
do not have vertical asymptotes at all.
Vertical asymptotes have functions 
Functions 
and 
have the same vertical asymptotes (when 
).
Functions and have the same vertical asymptotes (when 
). See attached diagram
Answer:
C. 18
Step-by-step explanation:
96 divided by 6 = 16
16+2=18
