Answer:
12.42 = 1242 / 100;
4.6 = 46 / 10;
12.42 ÷ 4.6 = (1242 / 100) ÷ (46 / 10 ) = (1242 / 100) x (10 / 46 ) = ( 1242 / 46 ) x ( 100 / 10 ) = 27 x 10 = 270;
Step-by-step explanation:
Answer:
17-d=5
Step-by-step explanation:
Hope this helps :)
Point Form:
(2, 4), (1, 1)
Equation Form:
x = 2, y = 4
x = 1, y = 1
AK = 640
Δ ABC and ΔFJK are similar. They are small triangles.
ΔCDF is the big triangle.
640 / 2 = 320 m= CF
AC & FK= 320/2 = 160 m each
2AC = CF = 2FK
2(160) = 320 = 2(160)
BG = 20 m
20/160 = x / 320
20*320 = 160x
6400 = 160x
6400/160 = x
40 = x
Area of CDF = (40 m * 320 m)/2 = 12,800 / 2= 6,400 m²
Answer:
Step-by-step explanation:
Given that for a sample of eight bears, researchers measured the distances around the bears' chests and weighed the bears.
r = linear correlation coeff = 0.952
H_0: r =0\\
H_1 :r\neq 0
(Two tailed test)
r difference = 0.952
n=8
Std error = \sqrt{\frac{1-r^2}{n-2} } =0.12496
Test statistic t = 0.952/0.12496 = 7.618
Alpha = 0.05
df = 6
p value = 0.000267
This implies H0 is rejected.
There exists a linear relation between the variables and r cannot be 0
0.952^2 = 0.906=90.6% of variation in weight can be explained by the linear relationship between weight and chest size
