To find diver's final location relative to the surface of water we will subtract $10\frac{1}{2}$ from $-50\frac{1}{4}$ because diver dives away another $10\frac{1}{2}$ from his previous location of $-50\frac{1}{4}$ .

$-50\frac{1}{4} -10\frac{1}{2}$

Now we will convert our mixed fraction into improper fraction and then we will find a common denominator.

$\frac{-201}{4} -\frac{21}{2} =\frac{-201-42}{4}$

$=\frac{-243}{4}$

Now let us convert our answer in mixed fraction.

$=\frac{-243}{4}=[tex]-60\frac{3}{4}$ [/tex]

Therefore, diver's final location relative to the surface of the water is $-60\frac{3}{4}$ meters.

3 0

4 years ago

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In the given figure, angle ABC is an equilateral triangle. If AB//CE, prove that angle ACE = angle ECD

defon

Answer:

Step-by-step explanation:

Triangle ABC is an equilateral triangle, then:

=> angle ABC = angle BAC = angle ACB = 60 deg

AB // CE, according to alternative interior pair of angles theorem:

=> angle ACE = angle BAC = angle ABC = 60 deg (1)

B, C, and D are colinear, then:

angle ECD + angle ACE + angle ACB = 180 deg

=> angle ECD = 180 - angle ACE - angle ACB = 180 - 60 - 60 = 60 deg (2)

From (1) and (2):

=>angle ACE = angle ECD = 60 deg

3 0

3 years ago