keep in mind when doing a problem like this you have to distribute each value to the rest of the expression and in this case you're multiplying. so m x m + m x 5 + 1 x m + 1 x 5 = m^2 + 6m + 5
First two rolls have to be 1-4 that is 2/3 chance twice and the third can be 4or 5 2/3*2/3*1/3 + the chance that the fourth is the 5 or 6. 2/3*2/3*2/3*1/3
So the solution is : P=2/3*2/3*1/3 + 2/3*2/3*2/3*1/3
