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denis-greek [22]
2 years ago
8

The cattle at the Clinton Farm are fed 1/4 of a bale of hay each day. The horses are fed 2 times as much hay as the cattle. How

many bales of hay are the horses fed each day?
Write your answer as a fraction or as a whole or mixed number.
Mathematics
1 answer:
xz_007 [3.2K]2 years ago
7 0

Answer:

1/2 of a bale

Step-by-step explanation:

1/4 times 2 equals 1/2

You might be interested in
The two triangles are similar. Determine the values of x, y, and z.
insens350 [35]

Answer:

y= 20 m

x= 15 m

z= 22 degree

Step-by-step explanation:

15+x=30 m

x=30-15

x= 15 m

z-18=40

z= 40-18

z= 22m

8 0
2 years ago
I need help solving this problem
Elena L [17]
Use the given values in the compound interest formula to solve for time, n.

A is the final amount of money, $2800
P is the initial or starting amount $1900
i is the interest rate as a decimal 0.025
n is time in years since it annual.

2800 = 1900(1 + 0.025)^n

2800 = 1900(1.025)^n

2800/1900 = (1.025)^n

28/19 = (1.025)^n

take the natural log of both sides to solve for exponent.

ln(28/19) = ln(1.025^n)

power rule of logarithmic moves exponent

ln(28/19) = n*ln(1.025)

ln(28/19) / ln(1.025) = n

put into a calculator

15.7 years = n
4 0
3 years ago
15. (3x + 6) - (3x - 6)
coldgirl [10]

Answer:

12

Step-by-step explanation:

Distribute the negative which would get your 3x + 6 -3x + 6. The 3x would cancel out and you would add 6+6 = 12

6 0
3 years ago
Read 2 more answers
A transformer increases the input voltage from 12V to 12,000V. What is the ratio of the number of wire turns on the primary coil
erma4kov [3.2K]

Answer:

\frac{n_p}{n_s}=\frac{1}{1000}

Step-by-step explanation:

Given voltage of primary coil is V_p=12V

And voltage of secondary coil is V_s=12,000V

A transformer is a device that contains primary and secondary coil. These coils are mounted on soft iron. The change in voltage depends upon the number of turns of primary coil (n_p) and secondary coil (n_s).

Following equation represents the relation between them.

\frac{V_s}{V_p} =\frac{n_s}{n_p}\\\\\frac{12,000}{12}=\frac{n_s}{n_p}\\\\1000=\frac{n_s}{n_p}

Then, ratio of the number of wire turns on the primary coil to the number of turns on the secondary coil is

\frac{n_p}{n_s}=\frac{1}{1000}

5 0
3 years ago
In 1999 Daniel was 146 cm tall. He grew to be 176 cm by the year 2006. What was Daniel's rate of growth over this period of his
andreyandreev [35.5K]

Answer:

he grows by 5 cm every year between 1999 and 2006

Step-by-step explanation:

This is a arithmetic progression problem with the formula;

T_n = a + (n - 1)d

We are told that In 1999 Daniel was 146 cm tall. He grew to be 176 cm by the year 2006.

Thus;

a = 146

d = 2006 - 1999 = 7

Thus;

176 = 146 + (7 - 1)d

176 - 146 = 6d

30 = 6d

d = 30/6

d = 5 cm

Thus, he grows by 5 cm every year between 1999 and 2006

3 0
3 years ago
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