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OleMash [197]
3 years ago
10

Can someone help me expand this polynomial?

Mathematics
2 answers:
Klio2033 [76]3 years ago
8 0

Answer:

Step-by-step explanation:

(k-p)(k-n)

=k^2 -(p+n)k+pn

this is the expanded form..

please mark me as the brainliest

Dahasolnce [82]3 years ago
4 0

。☆✼★ ━━━━━━━━━━━━━━  ☾  

Multiply the first 2 terms in each brackets

k x k = k^2

Multiply the two outside terms in the brackets

k x - n = -kn

Multiply the two inside terms

-p x k = -pk

Multiply the last two terms

-p x -n = pn

Place all the values together to get your answer of:

k^2 - kn - pk + pn

Have A Nice Day ❤    

Stay Brainly! ヅ    

- Ally ✧    

。☆✼★ ━━━━━━━━━━━━━━  ☾

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Add using the number line. 7+(−10) Drag and drop the word SUM to the correct value on the number line.
Amiraneli [1.4K]

Steps of adding 7+(-10) using number line are as following:


1) Draw a number line by ranging from -10 to +10.

2) Point out 7 on the number line.

3) Because -10 is added to 7 on the number line,  please move 10 numbers left to 7 on the number line. We always go left in addition of a negative number on the number line.

4) The number we reach -3 on left side would be our final sum.

5) From the number we can clearly see that moving 10 number on left to 7, we get -3.

Note: We are moving left because of negative sign in front of 10.


5 0
3 years ago
A grasshopper jumps straight up from the ground with an initial vertical velocity of 8 feet per second. After how many seconds w
vlabodo [156]

Answer:

Problem 1 : After 0.25 s

Problem 2 : The squirrel doesn't reach the ground before the nut

Step-by-step explanation:

Problem 1

This is a standard physics problem

The equation that defines the movement of the grasshopper given the initial velocity, and the acceleration is the following

Distance =  Do + Vo*t + 0.5*a*t^2

Where

Do is the initial distance.

(Do = 0, because the grasshopper is on the ground and we choose the reference system there)

Vo is the initial velocity = 8 feet/sec

a is the acceleration that is exerted on the body (in this case a = g = -9.8 m/s^2 = - 32.174 feet per second per second.)

t is the time

We substitute in the equation, and solve for t (time)

Distance =  Do + Vo*t + 0.5*a*t^2

(1 foot)=  (0)+ (8 feet/s)*t + 0.5*(-32.174 feet/s^2)*t^2

Solving this equation, we get that

t = 0.25 s

Problem 2

This problem is similar to the previous one

We apply the same formula

D =  Do + Vo*t + 0.5*a*t^2

But in this case, we are going in the opposite direction, and we have an initial distance.

Do = 27 feet

Vo is the initial velocity of the nut = -6 feet/s

D = 0  (Ground)

We substitute in the equation, and solve for t (time)

(0) =  (27) + (-6 feet/s)*t + 0.5*(-32 feet/s^2)*t^2

t = 1.125 s  <  2s

The nut reaches ground in 1.125 s, so the squirrel doesn't reach the ground before the nut

4 0
3 years ago
What is y=-5/3x-6 in standard form
andre [41]

Answer: 5x+3y=-18

Step-by-step explanation:

7 0
2 years ago
94÷4≈
Tanya [424]

Answer:

ok, te ayudaré

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25÷4=6.25

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37÷5=7.4

49÷2=24.5

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I hope it serves you, give me a crown please

7 0
2 years ago
Solve for Y I need help please
muminat
Bring y to one side and the rest to the other switching the positives to negative then you’ll get Y=114
6 0
3 years ago
Read 2 more answers
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