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Nesterboy [21]
3 years ago
7

imagine you are going on a rid in a spacecraft next to earth. Your trip takes one whole year. Describe earth's tilt in the north

ern hemisphere during your trip. What happens as a result of the tilt?
Physics
1 answer:
mylen [45]3 years ago
8 0
You will have to fly around the whole earth to get to your landing station
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A golf ball strikes a hard, smooth floor at an angle of 39.8 ° and, as the drawing shows, rebounds at the same angle. The mass o
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The magnitude of the impulse is 1.33 kg m/s

Explanation:

please look at the solution in the attached Word file

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3 years ago
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n a downhill ski race, surprisingly, little advantage is gained by getting a running start. (This is because the initial kinetic
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Answer:

Explanation:

a ) starting from rest , so u = o and initial kinetic energy = 0 .

Let mass of the skier = m

Kinetic energy gained = potential energy lost

= mgh = mg l sinθ

= m x 9.8 x 70 x sin 30

= 343 m

Total kinetic energy at the base = 343 m  + 0 = 343 m .

b )

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Total kinetic energy at the base

= 3.125 m  + 343 m

= 346.125 m

c ) It is not surprising as energy gained due to gravitational force by the earth is enormous . So component of energy gained due to gravitational force far exceeds the initial kinetic energy . Still in a competitive event , the fractional initial kinetic energy may be the deciding factor .

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3 years ago
1)Which statement best describes energy in an open system?
zimovet [89]
B an open system flow both 
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2 years ago
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Thermal energy is added to a sample, its particles move ?
8_murik_8 [283]
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4 0
3 years ago
Enterprising students set an enormous slip-n-slide (a plastic sheetcovered in water to reduce friction) on flat ground. If the s
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Answer:

a = -0.05 m/s² (negative sign shows deceleration)

Explanation:

In order, to find out the minimum average acceleration for a student starting at 5 m/s to slide to the end, we can use 3rd equation of motion. 3rd equation of motion is given as follows:

2as = Vf² - Vi²

where,

a = minimum acceleration required = ?

s = minimum distance covered = 250 m

Vf = Final Speed = 0 m/s (for minimum acceleration the student will barely cover 250 m and then stop)

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Therefore,

2a(250 m) = (0 m/s)² - (5 m/s)²

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<u>a = -0.05 m/s²</u> (negative sign shows deceleration)

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