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Nesterboy [21]
3 years ago
7

imagine you are going on a rid in a spacecraft next to earth. Your trip takes one whole year. Describe earth's tilt in the north

ern hemisphere during your trip. What happens as a result of the tilt?
Physics
1 answer:
mylen [45]3 years ago
8 0
You will have to fly around the whole earth to get to your landing station
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An 8 kg mass moving at 8 m/s collides with a 6 kg mass
steposvetlana [31]

Answer:

10 m/s

Explanation:

Momentum before collision = momentum after collision

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(8 kg)(8 m/s) + (6 kg)(6 m/s) = (8 kg)(5 m/s) + (6 kg) v

64 kg m/s + 36 kg m/s = 40 kg m/s + (6 kg) v

60 kg m/s = (6 kg) v

v = 10 m/s

3 0
4 years ago
Using the same cost and time estimates, consider any trade-offs that SciTech may have to make to complete the project.
ch4aika [34]

Answer:  

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Hope this helps :)

4 0
3 years ago
Read 2 more answers
M (b) Calculate the speed of an electron that is accelerated through the same electric potential difference.
MaRussiya [10]

The speed of a electron that is accelerated from rest through an electric potential difference of 120 V  is 6.49\times10^6m/s

<h3>How to calculate the speed of the electron?</h3>

We know, that the  energy of the system is always conserved.

Using the Law of Conservation of energy,

\triangle K+\triangle U=0

Here, K is the kinetic energy and U is the potential energy.

Now, substituting the formula of U and K, we get:

(\frac{1}{2} mv^2)+(-q\triangle V) =0------(1)

Here,

m is the mass of the electron

v is the speed of the electron

q is the charge on the electron

V is the potential difference

Let v_f and v_i represent the final and initial speed.

Here, v_i =0

Solving for v_f, we get:

v_f=\sqrt{\frac{-2q\triangle V}{m} }

=\sqrt{\frac{2\times1.602\times10^{-19}\times 120}{9.109\times10^{-31}} }

=6.49\times10^6m/s

To learn more about the conservation of energy, refer to:

brainly.com/question/2137260

#SPJ4

4 0
2 years ago
In 1998, scientists discovered that the expansion of the universe has been accelerating.
Gnom [1K]

Answer:the answer should be dark energy

Explanation:

3 0
4 years ago
Read 2 more answers
What is the magnitude of the force needed to keep a 60. -newton rubber block moving across level, dry asphalt in a straight line
OverLord2011 [107]

Answer:

A force of μk⋅60N is needed to keep a 60-newton rubber block moving across level, dry asphalt in a straight line at a constant speed.

Explanation:

6 0
2 years ago
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