3 years ago

A bowler who always left the same three pins standing could be considered a(n) ____ bowler.

1 answer:

4 0

A bowler who always left the same 3 pins standing could be considered a C. Precise bowler as from bowling countless number of times he has observed the same amount of pins knocked down each time.

You might be interested in

Manuel is holding a 5 kg box. How much force us the box exerting on him? in what direction

Free_Kalibri [48]

It will be 49 Newtons of force in the down direction. To find the force in newtons, you multiply the mass (5 kg) by the gravity (which if 9.8).

3 0

3 years ago

How many stars are there in an Open Cluster?*

Step2247 [10]

Answer:

Very few

Most open clusters form with at least 100 stars

Brainly, please.

4 0

3 years ago

Jupiter has the strongest gravity of any planet in our solar system. Which quantity will be a maximum there?

Mamont248 [21]

weight will be maximum there

3 0

2 years ago

After the same car leaves the platform, gravity causes it to accelerate downward at a rate of 9.8 m/s2. What is the gravitationa

Simora [160]

The gravitational force on the car is

(9.8 m/s^2) x (the car's mass in kg).

The unit is newtons.

7 0

3 years ago

point) A tank in the shape of an inverted right circular cone has height 5 meters and radius 4 meters. It is filled with 4 meter

zysi [14]

Answer:

W = 907963.50 J = 907.96 J

Explanation:

Note: Refer to the figure attached

Now, from the figure we have similar triangles ΔAOB and ΔCOD

we have

$\frac{5}{4}=\frac{x}{r}$

$r=\frac{4x}{5}$

Now, the work done to empty the tank can be given as:

$W = \int\limits^4_0 {(5-x)\rho\times g A} \, dx$

$W = \int\limits^4_0 {(5-x)1080\times 9.8 (\pi r^2)} \, dx$

$W = \int\limits^4_0 {(5-x)\times10584\times (\pi (\frac{4x}{5})^2)} \, dx$

$W = 6773.76\pi\int\limits^4_0 {(5-x)x^2)} \, dx$

$W = 6773.76\pi[\frac{5}{3}x^3-\frac{1}{4}x^4]^4_0$

$W = 6773.76\pi[\frac{128}{3}]$

W = 907963.50 J = 907.96 J

7 0

3 years ago