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Rama09 [41]
3 years ago
7

A bowler who always left the same three pins standing could be considered a(n) ____ bowler.

Physics
1 answer:
RideAnS [48]3 years ago
4 0
A bowler who always left the same 3 pins standing could be considered a C. Precise bowler as from bowling countless number of times he has observed the same amount of pins knocked down each time.
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Review. For a certain type of steel, stress is always proportional to strain with Young's modulus 20 × 10¹⁰ N/m² . The steel has
timurjin [86]

1.58\times 10^{-4}\ \mathrm{s}$ is the time interval elapses before the back end of the rod receives the message that it should stop.

Given:

Length of the rod, L = 80 cm = 0.800 m

Young's modulus, Y = 20 \times 10^{10}\;N/m^{2}

steel density, \rho = 7.86 \times 10^{3}\;kg/m^{3}

The speed of the wave in the rod is,

$v = \sqrt{\frac{Y}{\rho}} = \sqrt{\frac{20\times 10^{10}\ \mathrm{N/m^2}}{7.86\times 10^3\ \mathrm{kg/m^3}}} = 5044\ \mathrm{m/s}$

Consequently, the length of the rod's end is traveled by the wave in at

$t=\frac{L}{v} = \frac{0.800\ \mathrm{m}}{5044\ \mathrm{m/s}} = 1.58\times 10^{-4}\ \mathrm{s}$

Hence, 1.58\times 10^{-4}\ \mathrm{s}$ is the time interval elapses before the back end of the rod receives the message that it should stop.

<h3>What are Newtons Laws?</h3>

The three fundamental laws of classical mechanics known as Newton's laws of motion describe how an object's motion and the forces acting on it interact. The following paraphrase of these statutes is available

Unless a force acts upon a body, it remains at rest or in continual straight-line motion.

When a force acts on a body, the force is equal to the time rate at which the body's momentum changes.

When two bodies exert force on one another, the direction and amount of the force are opposed.

Isaac Newton first identified the three laws of motion in his 1687 book Philosophize Naturalis Principia Mathematica (Mathematical Principles of Natural Philosophy).

They served as the cornerstone for classical mechanics as Newton used them to examine and explain the motion of numerous physical objects and systems. The conceptual foundations of classical physics have been reconstructed in several ways since Newton, utilizing various mathematical techniques that have revealed insights that were hidden in the original, Newtonian formulation.

To know more about Newtons Laws, visit:

brainly.com/question/27573481

#SPJ4

7 0
1 year ago
A charged particle enters into a uniform magnetic field such that its velocity vector is perpendicular to the magnetic field vec
Phoenix [80]

Answer:

The particle path will follow

(d) a circular path

Explanation:

When a charged particle having charge of magnitude 'q' enters into a magnetic field such that its velocity vector '\vec{V}' is perpendicular to the direction of the magnetic field '\vec{B}', then it will experience a force, called Lorentz force (\vec{F_{L}}), given by

\vec{F_{L}} = \vec{V} \times \vec{B}

As shown in the figure, the magnetic field is directed perpendicular to the plane and towards the plane (as shown by the circle and 'X'-sign) and the velocity vector is from left to right on the plane.

According to the property of cross-product, the Lorentz force (F_{L}) acting on the particle will be perpendicular to the instantaneous position of the particle, making the path of the particle to be a circular path,as shown in the figure.

7 0
3 years ago
A Cessna aircraft has a liftoff speed of 120 km/h What minimum constant acceleration does the aircraft require to be airborne af
Lady_Fox [76]

Answer:

<h3>2.3125m/s²</h3>

Explanation:

Using the equation of motion v² = u²+2aS

v is the final velocity = 120km/hr

120km/hr = 120 * 1000/1 * 3600 = 33.3m/s

u is the initial velocity = 0m/s

a is the acceleration

S is the distance covered = 240m

On substituting the given parameters

33.3² = 0²+2a(240)

33.3² = 480a

1110 = 480a

a = 1110/480

a = 2.3125m/s²

Hence the minimum constant acceleration that the aircraft require to be airborne after a takeoff run of 240 m is 2.3125m/s²

4 0
3 years ago
A student carries a very heavy backpack. To lift the backpack off the ground, the student must apply 80 N of force to do so. The
Xelga [282]

The work done on the backpack by the student applies 80 N of force to lift the backpack 1.5 m is 120J.

<h3>How to calculate work done?</h3>

Work done is a measure of energy expended in moving an object; most commonly, force times distance.

It is said that no work is done if the object does not move, hence, the work done on an object can be calculated as follows:

Work done = Force × Distance

According to this question, a student carries a very heavy backpack and to lift the backpack off the ground, the student must apply 80 N of force to lift the backpack 1.5 m.

Work done = 80N × 1.5m

Work done = 120J

Therefore, the work done on the backpack by the student applies 80 N of force to lift the backpack 1.5 m is 120J.

Learn more about work done at: brainly.com/question/28172139

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8 0
2 years ago
A force of 6 N acts on a 33 kg object for 9 seconds. What is the objects change in velocity?
GuDViN [60]
Acceleration = change in velocity/time
By F = ma,
6 = 33 x change in velocity / 9
change in velocity = +1.636 m/s
4 0
3 years ago
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