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Norma-Jean [14]
3 years ago
8

Twice the sum of a number and seven is three times the number.

Mathematics
2 answers:
Trava [24]3 years ago
8 0
The equation will be 2x + 7 = 3x

subtract 2x from bothsides, you get 7 = x

so x is equal to 7 

EDITED

sorry, i didnt read the sum part, so my answer is considered wrong ahaha

2(x+7) equals 3x

distribute, you get 2x+14=3x

then subtract 2x,

the answer for x is 14


Otrada [13]3 years ago
7 0
X= in the number searched
2(x+7)= is the twice the sum of this number and seven.
3x= is three times the number

Because the twice the sum of a number and seven is three times the number, we suggest the following equation:

2(x+7)=3x
2x+14=3x
3x-2x=14
x=14

Answer: the number is 14. 
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At a movie theatre adult tickets cost $10 and child ticjets cost $6. Which equation can be used to find s, the number of dollars
timurjin [86]

Answer:

s = 10k + 30

Step-by-step explanation:

Cost of Adults ticket = $10 per adult

Cost of Ticket = $6 per child

Number of adults = k

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Total cost = (Cost per adult * number of adults) + (Cost per child * Number of children)

s = ($10 * k) + ($6 * 5)

s = $10k + $30

s = 10k + 30

4 0
3 years ago
6<br> (<br> f<br> +<br> 4<br> )<br> +<br> 2<br> (<br> f<br> +<br> 4<br> )
Helga [31]

6(f+4) + 2(f+4)

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6f+24 + 2f + 8

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4 0
3 years ago
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Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour
UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

C(t) = C(0)e^{rt}

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So C(0) = 110

Husband

Half life of 4 hours. So

C(4) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{4r}

e^{4r} = 0.5

Applying ln to both sides

\ln{e^{4r}} = \ln{0.5}

4r = \ln{0.5}

r = \frac{\ln{0.5}}{4}

r = -0.1733

So for the husband

C(t) = 110e^{-0.1733t}

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.1733t}

C(11) = 110e^{-0.1733*11} = 16.35

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

C(10) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{10}

e^{10r} = 0.5

Applying ln to both sides

\ln{e^{10r}} = \ln{0.5}

10r = \ln{0.5}

r = \frac{\ln{0.5}}{10}

r = -0.0693

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.0693t}

C(11) = 110e^{-0.0693*11} = 51.33

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0
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gogolik [260]

Answer:

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Step-by-step explanation:

What we have here is as follows;

if there are x 3-cent stamps, then there are 4x 10-cent stamps

So the number of 2-cent stamps is 1 less than 3 cent stamps and that will be x-1 2 cent stamps

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Total value is thus;

2b + 40b + 40 + 3b + 3 = (45b + 43) cents

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