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Viktor [21]
3 years ago
8

A ramp with a mechanical advantage of 8 lifts objects to a height of 1.5 meters how long is the ramp

Physics
1 answer:
AlekseyPX3 years ago
5 0

<u>Given data:</u>

M.A. =  8 (No units),

Ramp height (h)= 1.5 m, lifted,

Determine how long is the ramp=?

<em>General formula </em>

<em> Mechanical Advantage = (Ramp length) ÷ (Ramp height),</em>

<em>                              M.A = l  ÷ h </em>

<em>                                   8 × 1.5 = l = 12 m long</em>

<em>length of the ramp l ramp = 12 m</em>



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3 years ago
Calculate the average induced voltage between the tips of the wings of an airplane flying above East Lansing at a speed of 885 k
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Answer:

=0.855V

Explanation:

The induced voltage can be calculated using below expression

E =B x dA/dt

Where dA/dt = area

B= magnetic field = 6.90×10-5 T.

We were given speed of 885 km/h but we will need to convert to m/s for consistency of unit

speed = 885 km/h

speed = 885 x 10^3 m/hr

speed = 885 x 10^3/60 x60 m/s

speed = 245.8 m/s

If The aircraft wing sweep out" an area

at t= 50.4seconds then we have;

dA/dt = 50.4 x 245.8

= 123388.32m^2/s

Then from the expression above

E =B x dA/dt substitute the values of each parameters, we have

E = 6.90 x 10^-5 x 12388.32 V

E =0.855V

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6 0
3 years ago
This same experiment is performed on the international space station. What is the primary issue with performing this experiment
lions [1.4K]

Answer:

Difference in experimental data.

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There is difference of experimental value between the experiment that is performed on the earth and on the international space station because presence of gravity. The result of the experiment on the earth is different due to the presence of gravity that contributes in the result of the experiment as compared to international space station where no gravity is present so there is high difference of the numerical value of the result of both experiments of earth and international space station.

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A rigid tank whose volume is unknown is divided into two parts by a partition. One side of the tank contains an ideal gas at 935
a_sh-v [17]

Answer:

2805 °C

Explanation:

If the gas in the tank behaves as ideal gas at the start and end of the process. We can use the following equation:

P=RTn/V

The key issue is identify the quantities (P,T, V, n) in the initial and final state, particularly the quantities that change.

In the initial situation the gas have an initial volume V_{i}, temperature T_{i}, and pressure P,.

And in the final situation the gas have different volume V_{f} and temeperature T_{f}, the same pressure P,, and the same number of moles n,.

We can write the gas ideal equation for each state:

P=RT_{i}n/V_{i} and P=RT_{f}n/V_{f}, as the pressure are equals in both states we can write

RT_{i}n/V_{i} = RT_{f}n/V_{f}

solving for T_{f}

T_{f} = T_{i}/V_{i} * V_{f} (*)

We know T_{i}  = 935 °C, and that the V_{f} (the complete volume of the tank) is the initial volume V_{i} plus the part initially without gas which has a volume twice the size of the initial volume (read in the statement: the other side has a volume twice the size of the part containing the gas). So the final volume  V_{f}= V_{i} + 2V_{i}=3V_{i}

Replacing in (*)

T_{f} = 935/V_{i} * 3V_{i} = 935*3= 2805

7 0
3 years ago
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