Answer:
773.15K
Explanation:
Temperature is measured in different units, however, the standard or absolute temperature unit is Kelvin (K).
To convert the temperature of a black body, which is 500°C to Kelvin, we use;
T(K) = T(°C) + 273.15
T(K) = 500°C + 273.15
T(K) = 773.15K
Hence, the temperature of the blackbody at 500°C will be 773.15 K for it to radiate twice as much energy per second.
Answer:
a = 8.951 m/s²
Explanation:
given,
angle = 0.52 radians
μ_s = 0.84
μ_k = 0.48
acceleration = ?
using
F + f = m a
mg sin θ + μk mg cos θ = m a
a = g sin θ + μk g cos θ
a = 9.8 x sin 0.52 + 0.48 x 9.8 x cos 0.52
a = 4.869 + 4.082
a = 8.951 m/s²
the magnitude of acceleration is a = 8.951 m/s²
Temperature: Kelvin or degree Celsius; thermometer
Length: meter and its fractions and multiples; ruler
Volume: liter or cubic meter, mm, cm, km etc.; ruler for regular solids or empty spaces, graduated cylinder or kitchen measuring cup for liquids and irregular solids
Mass: kilogram and its multiples and fractions; balance with calibrated samples, or scale with knowledge of local gravity, or methods of applying known force and measuring acceleration
Answer:
Explanation:
decrease in energy of the transferred charge
= Voltage x charge
= 2.86 x 10⁹ x 23.1
= 66.067 x 10⁹ J
the final speed of the automobile be V
1/2 m v² = 66.067 x 10⁹
v² = 66.067 x 10⁹ x 2 / 1519
= .08698 x10⁹
= 87 x 10⁶
v = 9.32 x 10³ m / s
Answer:
Explanation:
Balance force ( W ) = 85 N
a) moving upward with constant velocity (V ) = 7.9 m/s.
The reading will not change since it is moving with constant velocity
W = 85 N
b) Moving upward with V = 7.9 m/s and decelerating at the rate of (a ) = 1.1 m /s²
The net force ( F ) = W - ma
where m = W/g = 85/9.81 = 8.6646 kg
F = 85 - 8.6646 * 1.1 = 75.4689 N
