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Sindrei [870]
3 years ago
7

A ball starts from rest. It rolls down a ramp and reaches the ground after 4 seconds. Its final velocity when it reaches the gro

und is 7.0 meters/second. The initial velocity of the ball is meters/second, and its acceleration is meters/second2. NextReset
Physics
2 answers:
Sidana [21]3 years ago
8 0

Answer:

0 and 1.75

Explanation:

Hunter-Best [27]3 years ago
3 0
If it starts at rest the initial velocity is 0.
For an acceleration, a, and time, t, the velocity is v=at. Since at t=4, v=7, then a=7/4=1.75m/s^2
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What happens to the free energy released as electrons are passed from photosystem II to photosystem I through a series of electr
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<span>It is used to establish and maintain a proton gradient.</span>
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Work-Energy Theorem: A 4.0 kg object is moving with speed 2.0 m/s. A 1.0 kg object is moving with speed 4.0 m/s. Both objects en
allsm [11]

The same braking force does work on these objects to slow them down. The work done is equal to their change in kinetic energy:

FΔx = 0.5mv²

F = force, Δx = distance traveled, m = mass, v = speed

Isolate Δx:

Δx = 0.5mv²/F

Calculate Δx for each object.

Object 1: m = 4.0kg, v = 2.0m/s

Δx = 0.5(4.0)(2.0)²/F = 8/F

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Δx = 0.5(1.0)(4.0)²/F = 8/F

The two objects travel the same distance before stopping.

4 0
2 years ago
A train travels 50 kilometers in 4 hours, and then 74 kilometers in 2 hours. What is its average speed?
olga55 [171]

Answer:

37.65

Explanation:

50/4 + 74/2

4 0
2 years ago
Read 2 more answers
A 200g piece of iron is heated at 100C. It is than dropped into water to bring its temperature down to 22C. What is the amount o
gizmo_the_mogwai [7]

Answer:

6926.4J

Explanation:

Given parameters:

Mass of iron  = 200g

Initial temperature  = 100°C

Final temperature  = 22°C

Unknown:

Amount of heat transferred to the water  = ?

Solution:

The quantity of heat transferred to the water is a function of mass and temperature of the iron;

 H  = m c Ф

m is the mass of the iron

Ф is the change in temperature

C is the specific heat capacity of iron = 0.444 J/g°C

Now;

 insert the parameters and solve;

      H  = 200 x 0.444 x (100-22)

      H = 6926.4J

8 0
3 years ago
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