With what speed would mail pass through the center of the Moon if falling in a tunnel that runs through the center
1 answer:
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Here, height is given which will be the distance for a freely falling object.
The velocity will be
and the acceleration will be
In this way, the formula works.
Answer:
Please refer to the figure.
Explanation:
The crucial point here is to calculate the enclosed current. If the current I is flowing through the whole cross-sectional area of the wire, the current density is
The current density is constant for different parts of the wire. This idea is similar to that of the density of a glass of water is equal to the density of a whole bucket of water.
So,
This enclosed current is now to be used in Ampere’s Law.
Here, represents the circular path of radius r. So we can replace the integral with the circumference of the path,
.
As a result, the magnetic field is
