In 1 hour, the hour hand sweeps across 1/12 of the clock's face. In 40 min, the hour hand travels (40 min)/(60 min) = 2/3 of the path it covers in an hour, so a total of 1/12 × 2/3 = 1/18 of the clock's face. This hand traces out a circle with radius 0.25 m, so in 40 min its tip traces out 1/18 of this circle's radius, or
1/18 × 2<em>π</em> (0.25 m) ≈ 0.087 m
The minute hand traverses (40 min)/(60 min) = 2/3 of the clock's face, so it traces out 2/3 of the circumference of a circle with radius 0.31 m:
2/3 × 2<em>π</em> (0.31 m) ≈ 1.3 m
The second hand completes 1 revolution each minute, so in 40 min it would fully trace the circumference of a circle with radius 0.34 m a total of 40 times, so it covers a distance of
40 × 2<em>π</em> (0.34 m) ≈ 85 m
Given forceF
1
=5N and F
2
=7N and θ=60
We know resultant force F=
5
2
+7
2
+2(5)(7)cos60
F=
25+49+35
F=
109
it's your answer
Wow I have no idea kid............
Answer: 20m/s.
Explanation:
Remember the second Newton's law:
F = a*m
This is:
The net force acting on an object is equal to the mass of the object times the acceleration of the object.
In this case, we have a force of 5N pushing the object to the right.
We also have a force of 5N pushing the object to the left.
These forces act on opposite directions.
Then the net force will be equal to the difference of these forces, this is:
F = 5N - 5N = 0N
Then the net force is 0N, then we have:
0N = m*a
0N/m = 0m/s^2 = a
This means that the acceleration of the object is 0, then the velocity of the object does not change.
This means that if the object was moving at a constant velocity of 20m/s, the velocity of the object will still be equal to 20m/s. (because the net force acting on the object is zero)
