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morpeh [17]
3 years ago
6

after the car leaves the platform , gravity causes it to accelerate downward at a rate of 9.8 m/s2. what is the gravitational fo

rce on the car?
Physics
1 answer:
alexandr1967 [171]3 years ago
5 0

The gravitational force on the car is the force popularly known
as the car's "weight".  Its magnitude is

            (9.8 m/s²) times (the car's mass, in kilograms) .

The unit of this quantity is [newton] .

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a large heavy truck and a baby carriage roll down a hill. Neglecting friction, at the bottom of the hill, the baby carriage will
sveticcg [70]

Answer:

please give me brainlist and follow

Explanation:

At the bottom of the hill, the baby carriage will likely have less momentum Therefore, option D is correct. Solution: ... Therefore, at the bottom of the hill, the heavy truck will have more momentum and baby carriage will have less momentum.

8 0
2 years ago
Two open organ pipes, sounding together, produce a beat frequency of 8.0 Hz . The shorter one is 2.08 m long. How long is the ot
s344n2d4d5 [400]

Answer:

The length of the longer pipe is L = 2.30 m

Explanation:

Given that:

Two open organ pipes, sounding together, produce a beat frequency of 8.0 Hz . The shorter one is 2.08 m long.

How long is the other pipe?

From above;

The formula for the frequency of open ended pipes can be expressed as:

f = \dfrac{nv}{2L}

where n = 1 ( since half wavelength exist between those two pipes)

v = 343 m/s  and L = 2.08 m

Thus, the shorter pipe produces a frequency of :

f = \dfrac{1*343}{2*2.08}

f = \dfrac{343}{4.16}

f =82.45 \ Hz

Also; we know that the beat frequency was given as 8.0 Hz

Then,

The lower frequency of the longer pipe = ( 82.45 - 8.0 )Hz

The lower frequency of the longer pipe = 74.45 Hz

Finally;

From the above equation; make Length L the subject of the formula. Then,

The length of the longer pipe is L = \dfrac{nv}{2f}

The length of the longer pipe is L = \dfrac{1*343}{2*74.45}

The length of the longer pipe is L = \dfrac{343}{148.9}

The length of the longer pipe is L = 2.30 m

6 0
3 years ago
A student is holding a stone at a certain height. The stone has 50 joules of potential energy and 0 joules of kinetic energy. Th
Hitman42 [59]

Answer:

d) The stone will have about 50 joules of kinetic energy and 0 joules of potential energy​ .

Explanation:

Given :

Initial Potential energy , P_i=50\ J .

Initial Kinetic energy , K_i=0\ J . ( because ball is in rest )

Now , we know , kinetic energy is maximum when an object reaches ground .

Also , potential energy is zero when an object is in ground .

We know , by conservation of energy :

Initial total energy = Final total energy

P_i+K_i=P_f+K_f\\\\50+0=0+K_f\\\\K_f=50 \ J

Therefore , option d) is correct .

6 0
3 years ago
The decomposition of water into hydrogen gas H2 and oxygen gas O2 can be modeled by the balanced chemical equation
Volgvan

2H2O->2H2+O2


This balanced chemical equation represents the decomposition of water into hydrogen gas and oxygen gas



3 0
3 years ago
Read 2 more answers
You are in charge of designing a movie stunt for a new Fast and Furious film. In this scene a stunt person has to jump from a br
blondinia [14]

Answer:

103.5 meters

Explanation:

Given that a stunt person has to jump from a bridge and land on a boat in the water 22.5 m below. The boat is cruising at a constant velocity of 48.3 m/s towards the bridge. The stunt person will jump up at 6.45 m/s as they leave the bridge.

The time the person will jump to a certain spot under the bridge can be calculated by using the formula below:

h = Ut + 1/2gt^2

since the person will fall under gravity, g = 9.8 m/s^2

Also, let assume that the person jump from rest, then, U = 0

Substitute h, U and g into the formula above

22.5 = 1/2 * 9.8 * t^2

22.5 = 4.9t^2

22.5 = 4.9t^2

t^2 = 22.5/4.9

t^2 = 4.59

t = \sqrt{4.592}

t = 2.143 seconds

From definition of speed,

speed = distance /time

Given that the boat is cruising at a constant velocity of 48.3 m/s towards the bridge, substitute the speed and the time to get the distance.

48.3 = distance / 2.143

distance = 48.3 * 2.143

distance = 103.5 m

Therefore,  the boat should be 103.5m away from the bridge at the moment the stunt person jumps?

3 0
3 years ago
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