Answer:
C =131.88 meters
Step-by-step explanation:
The circumference of a circle is given by
C = 2*pi*r
where r is the radius
C = 2 * pi * 21
C = 42 pi
If we approximate pi by 3.14
C = 42(3.14)
C =131.88 meters
Answer:
<h2>it will take 30 minutes</h2>
Step-by-step explanation:
obtain a formula
<h3>=> M = $0.10($p)+$25</h3>
<u>insert the value of p dollars</u>
<h3>=> M = $0.10(50) + 25</h3>
<u>multiply 50 by 0.10</u>
<h3>=> M = $5 + 25</h3>
<em> </em><u>add 25 + 5</u>
<h3><em><u>=></u></em> M = $30</h3>
<u>So it takes 30 minutes for international minutes</u> <em><u>Thank </u></em><em><u>You</u></em>
^_^
Answer:
um im pretty sure y = -15 and x = -17 but im pretty sure i did that wrong too lol sorry if it is wront
Step-by-step explanation:
The answer is 400 because u multiply 8 x 10= 80 x 5=400
<u>Part (a)</u>
The variable y is the dependent variable and the variable x is the independent variable.
<u>Part (b)</u>
The cost of one ticket is $0.75. Therefore, the cost of 18 tickets will be:
dollars
Now, we know that Kendall spent her money only on ride tickets and fair admission and that she spent a total of $33.50.
Therefore, the price of the fair admission is: $33.50-$13.50=$20
If we use y to represent the total cost and x to represent the number of ride tickets, the linear equation that can be used to determine the cost for anyone who only pays for ride tickets and fair admission can be written as:
......Equation 1
<u>Part (c)</u>
The above equation is logical because, in general, the total cost of the rides will depend upon the number of ride tickets bought and that will be 0.75x. Now, even if one does not take any rides, that is when x=0, they still will have to pay for the fair admission, and thus their total cost, y=$20.
Likewise, any "additional" cost will depend upon the number of ride tickets bought as already suggested. Thus, the total cost will be the sum of the total ride ticket cost and the fixed fair admission cost. Thus, the above Equation 1 is the correct representative linear equation of the question given.