Consider the charge for parking one car for t hours.
If t is more than 1, then the function is y=3+2(t-1), because 3 $ are payed for the first hour, then for t-1 of the left hours, we pay 2 $.
If t is one, then the rule y=3+2(t-1) still calculates the charge of 3 $, because substituting t with one in the formula yields 3.
75% is 75/100 or 0.75.
For whatever number of hours t, the charge for the first car is 3+2(t-1) $, and whatever that expression is, the price for the second car and third car will be
0.75 times 3+2(t-1). Thus, the charge for the 3 cars is given by:
3+2(t-1)+0.75[3+2(t-1)]+0.75[3+2(t-1)]=3+2(t-1)+<span>0.75 × 2[3 + 2(t − 1)].
Thus, the function which total parking charge of parking 3 cars for t hours is:
</span><span>f(t) = (3 + 2(t − 1)) + 0.75 × 2(3 + 2(t − 1))
Answer: C</span>
Penis______________________
Answer:
HCF=2*2=4
Step-by-step explanation:
Given : Shane wants to plant 28 marigold plants and 36 rose plants in his garden
To Find : the greatest number of rows possible each row has the same
number of marigold plants and the same number of rose plants.
Solution:
marigold plants = 28
rose plants = 36
To find the greatest number of rows possible if each row has the same
number of marigold plants and the same number of rose plants.
we need to find HCF of 28 and 36
28 = 2 x 2 x 7
36 = 2 x 2 x 3 x 3
HCF = 2 x 2 = 4
greatest number of rows possible is 4
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Answer: 80%
Explanation 4/5=.8
