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3 years ago

2. Calculate the density of a rock that has a mass of 21.58 grams and causes the water in a

Chemistry

1 answer:

mylen [45]3 years ago

3 0

Answer:

4.00 g/mL

Explanation:

Density is mass divided by volume (g/mL).

Mass of rock = 21.58

Volume of rock = 25.4 - 20.0 = 5.4mL

Density of rock = 21.58g / 5.4mL = 3.99629 g/mL

Round to the lowest number of significant figures which is three = 4.00 g/mL

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A car with a mass of 1,100 kg is moving with a velocity of 30 m/s due east . What is the moment?

dexar [7]

Momentum = (mass) x (velocity) = (1,100) x (30) =

33,000

kg-m/sec due east

6 0

3 years ago

g If 50.0 mL of a 0.75 M acetic acid solution is titrated with 1.0 M sodium hydroxide, what is the pH after 10.0 mL of NaOH have

V125BC [204]

Answer:

pH = 2.66

Explanation:

Acetic Acid + NaOH → Sodium Acetate + H₂O

First we calculate the number of moles of each reactant, using the given volumes and concentrations:

0.75 M Acetic acid * 50.0 mL = 37.5 mmol acetic acid

1.0 M NaOH * 10.0 mL = 10 mmol NaOH

We calculate how many acetic acid moles remain after the reaction:

37.5 mmol - 10 mmol = 27.5 mmol acetic acid

We now calculate the molar concentration of acetic acid after the reaction:

27.5 mmol / (50.0 mL + 10.0 mL) = 0.458 M

Then we calculate [H⁺], using the following formula for weak acid solutions:

[H⁺] = $\sqrt{C*Ka}=\sqrt{0.458M*1.76x10^{-5}}$

[H⁺] = 0.0028

Finally we calculate the pH:

pH = -log[H⁺]

pH = 2.66

8 0

3 years ago

How can one tell how much of each reactant will be used in a reaction?

Ostrovityanka [42]

To Tell how much of each reactant will be used in a reaction, we need to find which reactant is the Limiting Reagent.
All the reactants will be consumed in equal amount as that of L.R.

5 0

3 years ago

How many 3-liter balloons could the 12-L helium tank pressurized to 160 atm fill? Keep in mind that an "exhausted" helium tank i

vaieri [72.5K]

Answer:

The 12L helium tank pressurized to 160 atm will fill 636 3-liter balloons

Explanation:

It is possible to answer this question using Boyle's law:

$P_1V_1=P_2V_2$

Where P₁ is the pressure of the tank (160atm), V₁ is the volume of the tank (12L), P₂ is the pressure of the balloons (1atm, atmospheric pressure) And V₂ is the volume this gas will occupy at 1 atm, thus:

160atm×12L = 1atm×V₂

V₂ = 1920L

As the tank will never be empty, the volume of the gas able to fill balloons is the total volume minus 12L, thus the volume of helium able to fill balloons is:

1920L - 12L = 1908L

1908L will fill:

1908L× $\frac{1balloon}{3L}$ = 636 balloons

I hope it helps!

7 0

3 years ago

The reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O represents an acid-base tritration. The equivalence point occurs when 24.75 mL o

artcher [175]

            moles NaOH = c · V = 0.2432 mmol/mL · 24.75 mL = 6.0192 mmol
            moles H2SO4 = 6.0192 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 3.0096 mmol
Hence
            [H2SO4]= n/V = 3.0096 mmol / 38.94 mL = 0.07729 M
The answer to this question is [H2SO4] = 0.07729 M

6 0

3 years ago