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Alex17521 [72]
3 years ago
6

If a student did not remove all of the bubbles from inside the buret before reading the initial volume and beginning the titrati

on, will this cause the calculated concentration of the hydrochloric acid determined from that trial to be higher or lower than the actual concentration? explain your answer in complete sentences.
Chemistry
1 answer:
matrenka [14]3 years ago
5 0
Hello!

If there's an air bubble inside the buret,  and the bubble escapes the buret during the titration the initial volume lecture (Vi) would be lower (closer to 0) than the actual one, and the recorded consumed volume (ΔV=Vf-Vi) would be higher than the actual one and thus the calculated concentration of the hydrochloric acid would be higher than the real one.

Have a nice day!
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Answer:

The concentration of the HNO3 solution is 0.150 M

Explanation:

<u>Step 1:</u> Data given

Volume of the unknown HNO3 sample = 0.120 L

Volume of the 0.200 M Ba(OH)2 = 45.1 mL

<u>Step 2:</u> The balanced equation

2HNO3 + Ba(OH)2 ⟶ Ba(NO3)2 + 2H2O

<u>Step 3:</u> Calculate moles Ba(OH)2

moles Ba(OH)2 = molarity * volume

moles Ba(OH)2 = 0.200 M * 0.0451 L

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<u>Step 4:</u> Calculate moles of HNO3

For 1 mole of Ba(OH)2 we need 2 moles of HNO3

For 0.00902 moles of Ba(OH)2 we need 2*0.00902 = 0.01804 moles

<u>Step 5</u>: Calculate molarity of HNO3

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molarity = 0.01804 / 0.120 L

Molarity = 0.150 M HNO3

The concentration of the HNO3 solution is 0.150 M

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