Which enzyme is responsible for facilitating the hydrogen bonding

What is the balanced chemical equation for potassium and chlorine which form potassium chloride

ArbitrLikvidat [17]

Potassium metal + Chlorine Gas --------> Potassium Chloride
The chemical equation using symbols and formula is
K (s) + Cl2 (g) ---------> 2KCl (s)

3 0

3 years ago

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Sulphur burnt in oxygen forms sulphur dioxide. Calculate the heat given out when 1.6g of sulphur is burnt.

adell [148]

Answer:

Dont know

Explanation:

4 0

3 years ago

A compound is 7.74% hydrogen and 92.26% carbon by mass. At 100°C a 0.6883 g sample of the gas occupies 250 mL when the pressure

ycow [4]

Answer: The molecular formula for the compound is $C_6H_6$

Explanation:

We are given:

Percentage of C = 92.26 %

Percentage of H = 7.74 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 92.26 g

Mass of H = 7.74 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{92.26g}{12g/mole}=7.68moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{7.74g}{1g/mole}=7.74moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 7.68 moles.

For Carbon = $\frac{7.68}{7.68}=1$

For Hydrogen = $\frac{7.74}{7.68}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H = 1 : 1

The empirical formula for the given compound is $CH$

Calculating the molar mass of the compound:

To calculate the molecular mass, we use the equation given by ideal gas equation:

PV = nRT

Or,

$PV=\frac{m}{M}RT$

where,

P = pressure of the gas = 820 torr

V = Volume of gas = 250 mL = 0.250 L (Conversion factor: 1 L = 1000 mL )

m = mass of gas = 0.6883 g

M = Molar mass of gas = ?

R = Gas constant = $62.3637\text{ L. torr }mol^{-1}K^{-1}$

T = temperature of the gas = $100^oC=(100+273)K=373K$

Putting values in above equation, we get:

$820torr\times 0.250L=\frac{0.6883g}{M}\times 62.3637\text{ L torr }mol^{-1}K^{-1}\times 373K\\\\M=\frac{0.6883\times 62.3637\times 373}{820\times 0.250}=78.10g/mol$

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

We are given:

Mass of molecular formula = 78.10 g/mol

Mass of empirical formula = 13 g/mol

Putting values in above equation, we get:

$n=\frac{78.10g/mol}{13g/mol}=6$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(1\times 6)}H_{(1\times 6)}=C_6H_6$

Hence, the molecular formula for the compound is $C_6H_6$

8 0

3 years ago

Find the mass in grams of 2.00x10^23 molecules of F2

earnstyle [38]

Hello!

To find the mass in grams of 2.00 * 10²³ molecules of F₂ you'll need to apply the Avogadro's number, which tells the number of molecules in a mol of a substance, and the Molar Mass, which tells the weight of a mole of a substance. These two quantities are used in the following conversion factor:

$2,00*10^{23} moleculesF_2* \frac{1 mol F_2}{6,02*10^{23} moleculesF_2 }* \frac{37,997 g F_2}{1 mol F_2} \\ \\ =12,51 g F_2$

So, the mass of 2.00 * 10²³ molecules of F₂ is 12,51 g

Have a nice day!

4 0

3 years ago

How many bonded electron pairs and lone electron pairs does BH3 have?

marissa [1.9K]

BH3 VSEPR. Boron trihydride structure, BH3. On B, there are three bonded domains and no lone pairs, which give molecular geometries and trigonal planar electron-domain.

6 0

3 years ago