Can y’all please help !!!

Mathematics

1 answer:

Gemiola [76]3 years ago

4 0

Answer:

radius:5

center (2,-4)

Step-by-step explanation:

the equation of a circle is

$(x-h)^{2} + (y-k)^{2} = r^{2}$

where the center is (h,k) and the radius being r

this would mean that for your specific equation,

h=2

k=-4

and r= $\sqrt{25}$ = 5

so in order to graph the circle you start at (2,-4) and measure the distance of 5 units on your compass and graph it!

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If y varies directly as x, and y is 400 when x is r and y is r when x is 4, what is the numeric constant of variation in this re

Kipish [7]

$\bf \begin{array}{cccccclllll}
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{{ k}}&\cdot&x
\\
&& y={{ k }}x
\end{array}\\\\
-----------------------------\\\\
$

$\bf \textit{now, we also know }\qquad 
\begin{cases}
y=400\\
x=r\\
---\\
y=r\\
x=4
\end{cases}\implies 
\begin{cases}
400=kr\\
r=k4\\
----------\\
now\\
400=kr\implies \frac{400}{k}=\boxed{r}\\\\
thus\\\\
r=k4\implies \boxed{\frac{400}{k}}=4k
\end{cases}
\\\\\\
400=4k^2\implies \cfrac{400}{4}=k^2\implies 100=k^2\implies \sqrt{100}=k
\\\\\\
10=k\impliedby \textit{constant of variation}$