How do you know that 5, 7, 8, 9, 10, and 11 are not factors of 12?

Mathematics

1 answer:

Mrrafil [7]3 years ago

6 0

Answer :

Factors of 12 are

$1 \times 12 \\ 2 \times 6 \\ 3 \times 4.$

5 multiplied by any number can never give 12 . Multiples of 5 are
$5 \: 10 \: 15 \: 20$
7 multiples are
$7 \: 14 \: 21$
Same applies for all the listed numbers

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A circle is centered at the point (5,-4) & passes through the point (-3,2).

maxonik [38]

Equation of the circle:

$(x-5)^2+(y+4)^2=100$

Step-by-step explanation:

The equation of a circle is given by

$(x-x_0)^2+(y-y_0)^2=r^2$

where

$(x_0,y_0)$ are the coordinates of the center of the circle

r is the radius of the circle

For the circle in this problem, we know that:

(5,4) are the coordinates of the center

We also know that the circle passes through the point (-3,2), therefore we can calculate the radius as the distance between the point on the circle and the center of the circle:

$r=\sqrt{(-3-(5))^2+(2-(-4))^2}=\sqrt{(-8)^2+(6)^2}=\sqrt{64+36}=10$