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3 years ago

Can somebody answer this (on the picture) algebra question please

Mathematics

1 answer:

zheka24 [161]3 years ago

6 0

I am torn between B and D because increased means add, but I am going to go with B 1 - 3n. I choose B because in the D option it decreases not increases.

So the answer is B.) 1 - 3n
Hope this helps! - Alyssa

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Between which pair of numbers is the exact product of 379 and 8.

Bezzdna [24]

<span>Product means multiplication, so I would multiply 379 and 8.
379 x 8 = 3032
3032 is directly in between 3031 and 3033

brainly.com/question/122236
</span>

3 0

3 years ago

(PLEASE HELP ASAP)

lesya [120]

Answer:

Slope: -2
equation: y = -2x +5

Step-by-step explanation:

The given point is the y-intercept of the line, so the slope-intercept form of the equation of a line can be used:

y = mx + b . . . . for slope m and y-intercept b

Here, you have the slope given as ...

m = -2

y-intercept = 5

so the equation of the line is ...

y = -2x +5

_____

The y-intercept is the value of y when x=0. The point (x, y) = (0, 5) tells you the y-intercept is 5.

7 0

3 years ago

Common minimum of 8, 24, 40?

Brilliant_brown [7]

The common minimum of those three numbers is 120.

3 0

3 years ago

Read 2 more answers

the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0

3 years ago

SOLVE EACH EQUATION CHECK FOR EXTRANEOUS SOLTUIONS.

Anna007 [38]

Answer:

(i)x=-8

(ii)y>18

(iii)x>10

Step-by-step explanation:

I think the ans above is correct.

I hope it will help u....

4 0

3 years ago