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RSB [31]
2 years ago
15

joey can paint a room in 2 hours and chelsea can paint the same room in 3 hours. if they work together how long would it take to

paint the room
Mathematics
1 answer:
JulijaS [17]2 years ago
7 0

Answer:

1.2\ hours

Step-by-step explanation:

we know that

<em>Joey can paint a room in 2 hours</em>

That means

Joey can paint the 100% of the room-------> 2 hours

so

In 1 hour ------> can paint 100%/2=50%

<em>Chelsea can paint a room in 3 hours</em>

That means

C<em>helsea</em> can paint the 100% of the room-------> 3 hours

so

In 1 hour ------> can paint (100%/3)=33.33%

therefore

Joey and Chelsea in 1 hour can paint -----> 50%+33.33%=83.33%

by proportion

\frac{1}{83.33}\frac{hour}{\%} =\frac{x}{100}\frac{hour}{\%}\\ \\x=100/83.33\\ \\ x=1.2\ hours

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A train travels from station A to station B. If the train leaves station A and makes 75 km/hr, it arrives at station B 48 minute
SSSSS [86.1K]

Answer:

  • A) 290 km
  • B) 4 hours
  • C) 72.5 km/h

Step-by-step explanation:

Let distance be d and time t

<u>At 75 km/h speed the distance is</u>

  • d = 75(t - 48 min) = 75(t - 48/60 hours)

<u>At 50 km/h speed the distance</u> is

  • d = 50t + 40

<u>Since the distance is same, we get the equation:</u>

  • 75(t - 48/60) = 50t + 40
  • 75t - 75*4/5 = 50t + 40
  • 75t - 60 = 50t + 40
  • 75t - 50t = 40 + 60
  • 25t = 100
  • t = 4 hours

<u>A) The distance between A and B</u>

  • d = 50*5 + 40 = 290 km

<u>B) Time is </u>

  • 4 hours as found above

<u>C) The speed = d/t</u>

  • Speed = 290/4 = 72.5 km/h

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3 years ago
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Eight less than four times a number is less than 56.What are the possible values of that number
Gemiola [76]
We have the next inequation
8-4x<56

-4x<56-8
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4 0
3 years ago
Help me on this please
zalisa [80]

Answer:

1. (x, y) → (x + 3, y - 2)

Vertices of the image

a) (-2, - 3)

b) (-2, 3)

c) (2, 2)

2. (x, y) → (x - 3, y + 5)

Vertices of the image

a) (-3, 2)

b) (0, 2)

c) (0, 4)

d) (2, 4)

3. (x, y) → (x + 4, y)

Vertices of the image

a) (-1, -2)

b) (1, -2)

c) (3, -2)

4. (x, y) → (x + 6, y + 1)

Vertices of the image

a) (1, -1)

b) (1, -2)

c) (2, -2)

d) (2, -4)

e) (3, -1)

f) (3, -3)

g) (4, -3)

h) (1, -4)

5. (x, y) → (x, y - 4)

Vertices of the image

a) (0, -2)

b) (0, -3)

c) (2, -2)

d) (2, -4)

6. (x, y) → (x - 1, y + 4)

Vertices of the image

a) (-5, 3)

b) (-5, -1)

c) (-3, 0)

d) (-3, -1)

Explanation:

To identify each <u><em>IMAGE</em></u> you should perform the following steps:

  • List the vertex points of the preimage (the original figure) as ordered pairs.
  • Apply the transformation rule to every point of the preimage
  • List the image of each vertex after applying each transformation, also as ordered pairs.

<u>1. (x, y) → (x + 3, y - 2)</u>

The rule means that every point of the preimage is translated three units to the right and 2 units down.

Vertices of the preimage      Vertices of the image

a) (-5,2)                                   (-5 + 3, -1 - 2) = (-2, - 3)

b) (-5, 5)                                  (-5 + 3, 5 - 2) = (-2, 3)

c) (-1, 4)                                   (-1 + 3, 4 - 2) = (2, 2)

<u>2. (x,y) → (x - 3, y + 5)</u>

The rule means that every point of the preimage is translated three units to the left and five units down.

Vertices of the preimage      Vertices of the image

a) (0, -3)                                   (0 - 3, -3 + 5) = (-3, 2)

b) (3, -3)                                   (3 - 3, -3  + 5) = (0, 2)

c) (3, -1)                                    (3 - 3, -1 + 5) = (0, 4)

d) (5, -1)                                    (5 - 3, -1 + 5) = (2, 4)

<u>3. (x, y) → (x + 4, y)</u>

The rule represents a translation 4 units to the right.

Vertices of the preimage   Vertices of the image

a) (-5, -2)                               (-5 + 4, -2) = (-1, -2)

b) (-3, -5)                               (-3 + 4, -2) = (1, -2)

c) (-1, -2)                                (-1 + 4, -2) = (3, -2)

<u>4. (x, y) → (x + 6, y + 1)</u>

Vertices of the preimage      Vertices of the image

a) (-5, -2)                                  (-5 + 6, -2 + 1) = (1, -1)

b) (-5, -3)                                  (-5 + 6, -3 + 1) = (1, -2)

c) (-4, -3)                                   (-4 + 6, -3 + 1) = (2, -2)

d) (-4, -5)                                  (-4 + 6, -5 + 1) = (2, -4)

e) (-3, -2)                                  (-3 + 6, -2 + 1) = (3, -1)

f) (-3, -4)                                   (-3 + 6, -4 + 1) = (3, -3)

g) (-2, -4)                                  (-2 + 6, -4 + 1) = (4, -3)

h) (-2, -5)                                  (-2 + 3, -5 + 1) = (1, -4)

<u>5. (x, y) → (x, y - 4)</u>

This is a translation four units down

Vertices of the preimage      Vertices of the image

a) (0, 2)                                    (0, 2 - 4) = (0, -2)

b) (0,1)                                      (0, 1 - 4) = (0, -3)

c) (2, 2)                                     (2, 2 - 4) = (2, -2)

d) (2,0)                                     (2, 0 - 4) = (2, -4)

<u>6. (x, y) → (x - 1, y + 4)</u>

This is a translation one unit to the left and four units up.

Vertices of the pre-image     Vertices of the image

a) (-4, -1)                                   (-4 - 1, -1 + 4) = (-5, 3)

b) (-4 - 5)                                  (-4 - 1, -5 + 4) = (-5, -1)

c) (-2, -4)                                  (- 2 - 1, -4 + 4) = (-3, 0)

d) (-2, -5)                                 (-2 - 1, -5 + 4) = (-3, -1)

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3 years ago
What is 1/10 of 0.092?
bezimeni [28]
When you multiply by 1/10 you normally add another 0:
1/10 * 0.092=0.0092
6 0
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