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attashe74 [19]
3 years ago
7

scholars want to share 9 chocolate bars so that each scholar gets the same amount. How much chocolate bar will each scholar get?

Mathematics
1 answer:
bazaltina [42]3 years ago
8 0

I'm not exactly sure how to answer this question without knowing the number of scholars. However, if you do know the number of scholars, you can divide that number by 9. The quotient will give you the amount of chocolate each scholar can receive.

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Can someone please help me
Salsk061 [2.6K]

Answer:

B

Step-by-step explanation:

Area of pool = l × b

l = 6x and b = 3x - 5

Area = 6x(3x - 5)

Area = 18x² - 30x

4 0
3 years ago
What is the unit rate of $46 for 5 toys
Nookie1986 [14]
I think it would be $9.20 because 46 divided by 5 = 9.2
8 0
2 years ago
Jim drove 436 miles using 16 gallons of gas. At this rate, how many limes would he drive using 14 gallons of gas?
almond37 [142]
The ratio here is 16:436.
The easiest way to solve this is finding how many miles Jim can drive using just 1 gallon. We can do this by dividing both sides of the ratio by 16.

16÷16 is 1
436÷16 is 27.25
so our new ratio is 1 gallon:27.25 miles.

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7 0
2 years ago
A sample of 114 mortgages approved during the current year showed that 36 were issued to a single-earner family or individual. T
kodGreya [7K]

Answer:

a-1) Reject H0 if zcalc > 1.645

a-2) z=\frac{0.316 -0.28}{\sqrt{\frac{0.28(1-0.28)}{114}}}=0.8561  

a-3) ii. False

b) ii. No

c) iii. n π > 10 and n(1 − π ) > 10

Step-by-step explanation:

1) Data given and notation

n=114 represent the random sample taken

X=36 represent the people that were issued to a single-earner family or individual

\hat p=\frac{36}{114}=0.316 estimated proportion of people that were issued to a single-earner family or individual

p_o=0.28 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

(a-1) H0: π ≤ .28 versus H1: π > .28. Choose the right option. Reject H0 if zcalc > 1.645 Reject H0 if zcalc < 1.645 a b

We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.28.:  

Null hypothesis:p\geq 0.28  

Alternative hypothesis:p < 0.28  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

The rejection zone would be on this case :

Reject H0 if zcalc > 1.645

Since is a right tailed test

(a-2) Calculate the test statistic. (Round intermediate calculations to 2 decimal places. Round your answer to 4 decimal places.) Test statistic

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.316 -0.28}{\sqrt{\frac{0.28(1-0.28)}{114}}}=0.8561  

(a-3) The null hypothesis should be rejected.

False, since our calculated value is less than our critical value we Fails to reject the null hypothesis

(b) Is this a close decision?

False the calculated value is significantly less than the critical value so we FAIL to reject the null hypothesis with enough confidence.

(c) State any assumptions that are required.

In order to satisfy the conditions we need the following two requirements:

iii. n π > 10 and n(1 − π ) > 10

And are satisfied:

114*0.28=31.92>10

114(1-0.28)=82,08>10

7 0
3 years ago
What is the solution to 3x²+x+10=0
e-lub [12.9K]

Answer:

x = - 1/6 + √-119/6, and, - 1/6 - √-119/6

Step-by-step explanation:

Using the quadratic formula which is: - b ± √b² - 4ac / 2a

a = 3, b = 1, c = 10

- 1 ± √1² -4 * 3 * 10 / 2 * 3

- 1 ± √1 - 120 / 6

-1 ± √-119 / 6

= -1/6 + √119/6,               or                  - 1/6 - √-119/6

7 0
3 years ago
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