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3 years ago

scholars want to share 9 chocolate bars so that each scholar gets the same amount. How much chocolate bar will each scholar get?

1 answer:

8 0

I'm not exactly sure how to answer this question without knowing the number of scholars. However, if you do know the number of scholars, you can divide that number by 9. The quotient will give you the amount of chocolate each scholar can receive.

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HELP

3241004551 [841]

This might be the answer but I no sure

8 0

3 years ago

Find the velocity of a runner that complete 400 meters in 56 seconds

elena-s [515]

Answer:

Step-by-step explanation:

As long as the runner does not change direction, the velocity would be

Formula

d = r*t

r = d/t

Solution

r = 400 m / 56 s

r = 7.14 m/s

6 0

3 years ago

Read 2 more answers

The number 2017 can be expressed as the difference of the squares of two consecutive whole numbers. What is the sum of these two

SSSSS [86.1K]

Let x be the first number

X + 1 be the second number

(x+1)^2 – x^2 = 2017

X^2 + 2x +1 – x^2 = 2017

2x + 1 = 2017

2x = 2017 – 1

2x = 2016

X = 1008

X + 1 = 1009

Sum = 1008 + 1009 = 2017

8 0

3 years ago

Use separation of variables to solve dy dx − tan x = y2 tan x with y(0) = √3. Find the value of c in radians, not degrees

a_sh-v [17]

Answer:

$y(x)=tan(-log(cos(x))+\frac{\pi }{3} )$

Step-by-step explanation:

Rewrite the equation as:

$\frac{dy(x)}{dx}-tan(x)=y(x)^{2} *tan(x)$

Isolating $\frac{dy}{dx}$

$\frac{dy}{dx} =tan(x)+tan(x)*y^{2}$

Factor:

$\frac{dy}{dx} =tan(x)*(1+y^{2} )$

Dividing both sides by $(1+y^{2} )$ and multiplying them by $dx$

$\frac{dy}{1+y^{2} } =tan(x)dx$

Integrate both sides:

$\int\ \frac{dy}{1+y^{2} } = \int\ tan(x) dx$

Evaluate the integrals:

$arctan(y)=-log(cos(x))+C_1$

Solving for y:

$y(x)=tan(-log(cos(x))+C_1)$

Evaluating the initial condition:

$y(0)=\sqrt{3} =tan(-log(cos(0))+C_1)=tan(-log(1)+C_1)=tan(0+C_1)$

$\sqrt{3} =tan(C_1)\\arctan(\sqrt{3} )=C_1\\60=C_1$

Converting 60 degrees to radians:

$60degrees*\frac{\pi }{180degrees} =\frac{\pi }{3}$

Replacing $C_1$ in the diferential equation solution:

$y(x)=tan(-log(cos(x))+\frac{\pi }{3} )$

3 0

3 years ago

Figure this out for me.

Fiesta28 [93]

I’m sorry but I think you forgot to attach the picture of the problem to your question

7 0

2 years ago