ΔACD is similar to ΔBCD by AA similarity theorem
AD/AC = BD/BC
x/5 = 4.2/6
6x = 21
x = 3.5
Hope this helps! ;)
Answer:
I think the 1st one im not really sure tho
Step-by-step explanation:
Answer: x = 14 - 5y
y = 14/5 - x/5( if you solve for y )
2nd one x = 35/4 + y/4
y = -35 +4x ( solve for y )
The vertex of f(x) = 3x^2 + 12x − 8 is (2,28) absolute minimum
<h3>How to determine the vertex?</h3>
The equation is given as:
f(x) = 3x^2 + 12x − 8
Differentiate the function
f'(x) = 6x + 12
Set to 0
6x + 12 = 0
Divide through by 6
x + 2 = 0
Solve for x
x = -2
Substitute x = -2 in f(x) = 3x^2 + 12x − 8
f(2) = 3 *2^2 + 12 *2 − 8
Evaluate
f(2) = 28
This means that the vertex is (2,28)
A quadratic function is represented as:
f(x) =ax^2 + bx + c
When a is positive, then the vertex of the function is an absolute minimum.
This means that f(x) = 3x^2 + 12x − 8 has an absolute minimum vertex because 3 is positive
Read more about quadratic functions at:
brainly.com/question/18797214
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Hey there. The answer is A. 4/11.
To find the slope, look at the coordinates (-7, 2). Starting from there, we need to find the slope to go to the point (4, 6). We need to find the rise over run.
Look at the picture I attached. I hope you understand and find my answer helpful.