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tino4ka555 [31]
3 years ago
9

50 points i need to know how to plot these

Mathematics
1 answer:
svetlana [45]3 years ago
5 0

x is time and y is pencils that you have

'starts with 90' so at x=0, plot y=90

'gives away 15 every hour' so for every 1 hour, move 15 down on y

so at x=1, do 90-15=75 pencils

at x=2, do 75-15=60 pencils

etc

until you get to

x=6, do 15-15=0 pencils then stop because you can't give away 15 pencils when you have 0

see attachment for plot

I don't know how your segment tool works so you do it

if it draws a line, you only need 2 points, just do when x=0, y=90 and when x=6, y=0

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Tpy6a [65]
I think the answer is 29.4
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Find n.<br><br> 6/9 = n/36<br><br> n = (Blank)
mezya [45]
9*4=36 so you have to multiply the numerator and the denominator by 4 to get n.
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3 years ago
PLEASE HELP!!
I am Lyosha [343]
36 + 18 = 54

(1) 18/54 = 1/3 = 33%

43 + 24 = 67

(2) 24/67 = 36%




I hope these are right
3 0
3 years ago
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One hose can fill a goldfish pond in 36 ​minutes, and two hoses can fill the same pond in 20 minutes. Find how long it takes the
rjkz [21]

Answer:

45 minutes

Step-by-step explanation:

It is given that one hose can fill a goldfish pond in 36 minute

So the the first hose can fill goldfish pond \frac{1}{36} per minute

When both fill together then they fill in 20 minutes

So the the both  hose can fill goldfish pond \frac{1}{20} per minute

Let Goldfish pond filled by second hose  \frac{1}{x} per minute

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5 0
4 years ago
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A bank loaned out $17,500, part of it at the rate of 10% annual interest, and the rest at 14% annual interest. The total interes
Gennadij [26K]

Answer:

<u>$7 000</u> was loaned at 10 % and

<u>$10 500</u> was loaned at 14 %

Step-by-step explanation:

                 Let x = amount loaned at 10 %

Then 17 500 - x = amount loaned at 14 %

                0.10x = interest on 10 % loan

0.14(17 500 - x) = interest on 14 % loan

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\begin{array}{rcl}0.10x + 0.14(17 500 - x) & = & 2170.00\\0.10x + 2450 - 0.14x & = & 2170.00\\2450 - 0.04x & = & 2170.00\\-0.04x & = & -280\\\\x & = & \dfrac{-280}{-0.04}\\\\x & = & \mathbf{7000}\\\\\end{array}

<u>$7000</u> was loaned at 10 % and

<u>$10 500</u> was loaned at 14 %

Check:

\\begin{array}{rcl}0.10\times 7000 + 0.14(17 500 - 7000) & = & 2170\\700 + 0.14(10 500) & = & 2170\\700 + 1470 & = & 2170\\2170 & = & 2170\\\end{array}

OK.

3 0
3 years ago
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