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My name is Ann [436]
3 years ago
15

Can you give examples of carbon in our living environment?

Chemistry
2 answers:
sveticcg [70]3 years ago
5 0
Wastes
Fuel
Smoke
Gas
Toxic chemicals
REY [17]3 years ago
4 0
Our own bodies contain carbon - coal as well and plastics
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Determine the poh of 0.01 molar solution of carbonic acid
Veronika [31]

Hello!

Data:

Molar Mass of H2CO3 (carbonic acid)

H = 2*1 = 2 amu

C = 1*12 = 12 amu

O = 3*16 = 48 amu

------------------------

Molar Mass of H2CO3 = 2 + 12 + 48 = 62 g/mol

Now, since the Molarity and ionization constant has been supplied, we will find the degree of ionization, let us see:

M (molarity) = 0.01 M (Mol/L) → 1*10^{-2}\:M

Use: Ka (ionization constant) = 4.4*10^{-7}

\alpha^2 (degree\:of\:ionization) = ?

Ka = M * \alpha^2

4.4*10^{-7} = 1*10^{-2}*\alpha^2

1*10^{-2}*\alpha^2 = 4.4*10^{-7}

\alpha^2 = \dfrac{4.4*10^{-7}}{1*10^{-2}}

\alpha^2 = 4.4*10^{-7-(-2)}

\alpha^2 = 4.4*10^{-7+2}

\alpha^2 = 4.4*10^{-5}

\alpha = \sqrt{4.4*10^{-5}}

\boxed{\alpha \approx 2.09*10^{-5}}

Now, we will calculate the amount of Hydronium [H3O+] in carbonic acid (H2CO3), multiply the acid molarity by the degree of ionization, we will have:

[ H_{3} O^+] = M* \alpha

[ H_{3} O^+] = 1*10^{-2}* 2.09*10^{-5}

[ H_{3} O^+] = 2.09*10^{-2-5}

\boxed{[ H_{3} O^+] = 2.09*10^{-7}}

And finally, we will use the data found and put in the logarithmic equation of the PH, thus:

Data:

pH = \:?

[ H_{3} O^+] = 2.09*10^{-7}

apply the data to formula

pH = - log[H_{3} O^+]

pH = - log[2.09*10^{-7}]

pH = 7 - log\:2.09

pH = 7 - 0.32

\boxed{pH = 6.68}

Note:. The pH <7, then we have an acidic solution (weak acid).

Now, let's find pOH by the following formula:

pH + pOH = 14

6.68 + pOH = 14

pOH = 14 - 6.68

\boxed{\boxed{pOH = 7.32}}\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

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3 years ago
What grade percentage is developing, proficient, exceeding, and emerging?​
user100 [1]

Answer:

Grade A is the best percentage that is developing, proficient, exceeding, and emerging

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1 moL of a substance is equal to 6.02 x 1023 atoms or particles<br> True or false
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1 moL of a substance is equal to 6.02 x 10^23 atoms or particles , it true statement. This number is known as Avogadro number.  

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bond

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Answer:

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