When dealing with making diluted solutions from concentrated solutions, we can use the following formula
c1v1 = c2v2
where c1 and v1 are the concentration and volume of the concentrated solution respectively.
c2 and v2 are the concentration and volume of the diluted solution respectively
substituting these values in the above formula,
20 mL x 0.200 M = C x 250.0 mL
C = 0.0160 M
The oxidizing and reducing agent in the above redox reaction are hydrogen sulphide (H2S) and Chlorine (Cl) respectively.
<h3>What is an oxidizing and reducing agent?</h3>
An oxidizing agent is any substance that oxidizes, or receives electrons from another substance and as a result, becoming reduced.
On the other hand, a reducing agent is any substance that reduces or donates electrons to another and as a result becomes oxidized.
According to this reaction; H2S(aq) + Cl2(g) -> S(s) + 2HCI (aq)
- H2S accepts electrons from Cl2 and becomes reduced to S
- Cl2 donates electrons to H2S and becomes oxidized to HCl
Therefore, the oxidizing and reducing agent in the above redox reaction are hydrogen sulphide (H2S) and Chlorine (Cl) respectively.
Learn more about oxidizing agent at: brainly.com/question/10547418
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The answer gonna be: 1/2^n = 1/2^4 = 0.0625
So, 6.25% sample has not decayed yet!!!
