The answer is; endocytosis
This is a form of active transport that enable cells to import large particles that cannot pass across the membrane. It is a bulk transport system. The opposite of endocytosis s exocytosis where the cell expels large particles to the outside of the cell.
C. Both processes involve energy-carrier molecules.
It prevents being damaged and cross contamination from other objects that may disrupt the evidence
The genotype ratio is the proportion of different genotypes observed in the next generation from a genetic cross. The phenotypic ratio is the proportion of phenotypic traits observed from a genetic cross.
In this case, the genetic cross between a rose comb rooster (RRpp) and a pea comb rooster (rrPP) will produce the F1 generation:
F1 Generation:
- Genotype: 100% RrPp
- Phenotype: 100% walnut comb (R_P_)
F1 gametes:
- 1/4 RP; 1/4 Rp; 1/4 rP; 1/4 rp
Punnett square segregate alleles (F2):
1/4 RP 1/4 Rp 1/4 rP 1/4 rp
1/4 RP 1/16 RRPP 1/16 RRPp 1/16 RrPP 1/16 RrPp
1/4 Rp 1/16 RRPp 1/16 RRpp 1/16 RrPp 1/16 Rrpp
1/4 rP 1/16 RrPP 1/16 RrPp 1/16 rrPP 1/16 rrPp
1/4 rp 1/16 RrPp 1/16 Rrpp 1/16 rrPp 1/16 rrpp
Hence, the genotypic and phenotypic ratios in a cross between two F2 will be:
Genotypic ratio F2:
- 1/16 RRPP
- 1/8 RRPp
- 1/16 RRpp
- 1/8 RrPP
- 1/4 RrPp
- 1/8 Rrpp
- 1/16 rrPP
- 1/8 rrPp
- 1/16 rrpp
Phenotypic ratio F2:
- 9/16 walnut comb (R_P_)
- 3/16 rose comb (R_pp)
- 3/16 pea comb (rrP_)
- 1/16 single comb (rrpp)
Learn more in:
brainly.com/question/1185199?referrer=searchResults
