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Viktor [21]
4 years ago
6

Please help !

Mathematics
2 answers:
Vlada [557]4 years ago
6 0

Answer:

a

Step-by-step explanation:

0=3x²+20x+12

0=(3x+2)(x+6)

0=3x+2 0=x+6

-2=3x -6=x

-2/3=x

Alexus [3.1K]4 years ago
3 0

C. and A.

Edgenuit.y2020 bih

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eimsori [14]

Answer:

set middle number=x

then left side number=x-1

and right side number=x+1

(x-1)+x+(x+1)=30

3x=30

x=10

x-1=9

x+1=11

numbers are 9,10,11

4 0
3 years ago
Apply the distributive property to factor out the greatest common factor. 6+30=
Triss [41]

Answer:

6(1+5)

Step-by-step explanation:

The greatest common factor is 6

(6 + 30) = 6(1+5)

6(1+5) is the answer

Hope this helps :)

Have a nice day!

3 0
3 years ago
A point on the ground is 50 feet from my house. The angle of elevation to the top of the house is 48∘. Find the height of the ho
Mumz [18]

Answer:

55.5 feet

Step-by-step explanation:

the scenario is attached in the form of a picture

We have to find h.

We will use the trigonometric ratio of tan to find the height of the house.

tan\ 48 = \frac{h}{50}\\ 1.1106*50=h\\55.53=h

Hence the height of the house is 55.53 feet

Rounding off to nearest 10th

height = 55.5 feet ..

3 0
4 years ago
Write the given expression as an algebraic expression in x. tan(2 cos^-1(x))
miv72 [106K]
\bf tan\left[ 2cos^{-1}(x) \right]\implies tan\left[ 2cos^{-1}\left( \frac{x}{1} \right) \right]
\\\\\\
\textit{if we say }cos^{-1}\left( \frac{x}{1} \right)=\theta\textit{  that means }tan\left[ 2cos^{-1}\left( \frac{x}{1} \right) \right]\iff tan(2\theta)\\\\
-----------------------------\\\\
cos^{-1}\left( \frac{x}{1} \right)=\theta\implies cos(\theta)=\cfrac{x}{1}\cfrac{\leftarrow adjacent=a}{\leftarrow hypotenuse=c}\\\\
-----------------------------\\\\


\bf \textit{again, using the pythagorean theorem to get the opposite side}
\\\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-a^2}=b\implies \pm\sqrt{1^2-x^2}=b
\\\\\\
\pm\sqrt{1-x^2}=b\\\\
-----------------------------\\\\
tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\implies tan(2\theta)=\cfrac{2\cdot \frac{\pm\sqrt{1-x^2}}{x}}{1-\left( \frac{\pm\sqrt{1-x^2}}{x} \right)^2}
\\\\\\

\bf tan(2\theta)=\cfrac{\frac{\pm2\sqrt{1-x^2}}{x}}{1-\frac{1-x}{x}}\implies 
tan(2\theta)=\cfrac{\frac{\pm2\sqrt{1-x^2}}{x}}{\frac{x-1+x}{x}}
\\\\\\
tan(2\theta)=\cfrac{\pm2\sqrt{1-x^2}}{x}\cdot \cfrac{x}{2x-1}
\implies 
tan(2\theta)=\cfrac{\pm 2\sqrt{1-x^2}}{2x-1}


6 0
4 years ago
What is the area of the shaded region below? ​
klasskru [66]

Answer:

42

Step-by-step explanation:

4x7=28

7x2=14

28+14=42

Hope this helps!

7 0
3 years ago
Read 2 more answers
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