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ddd [48]
3 years ago
13

Which would not be a step in finding the area of a circle( someone plz answerrrrrrr

Mathematics
1 answer:
bixtya [17]3 years ago
3 0

Answer:

D. Continue cutting smaller and smaller slices.

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Help!!!!! please!!!!!
wlad13 [49]

Answer:

50

Step-by-step explanation:

10(10)/2

100/2

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8 0
4 years ago
Plz answer the question I'll give brainliest
svlad2 [7]

Answer:

what question there is no question

6 0
3 years ago
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tara has two bags of marbles. the first bag contains 6 red marbles , 5 blue marbles and 4 green marbles tara will recomendly sel
vodka [1.7K]

well, in order to solve this we can put each marble into a fraction.

so for blue it would be 5 over 15 (5/15)

because there are 15 marbles in the bag but only 5 of them are blue!

but if you need a % then just divide the top by bottom

then you get a 33% chance of picking blue! hope this helps!

4 0
4 years ago
Simplify <img src="https://tex.z-dn.net/?f=7%5E%7B-2log_%7B7%7D3%7D" id="TexFormula1" title="7^{-2log_{7}3}" alt="7^{-2log_{7}3}
jasenka [17]

This expression is equivalent to:


[ 7^(log to the base 7 of 3)]^(-2), or    [3]^(-2)], or 1/9.

6 0
3 years ago
The heights of the trees for sale at two nurseries are shown below. Heights of trees at Yard Works in feet : 7, 9, 7, 12, 5 Heig
Troyanec [42]

Answer:

The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

Step-by-step explanation:

1). Height of the trees at Yard Works are = 7,9,7,12,5 feet

So mean height of the trees = (7+9+7+12+5)÷5

                                               = 40÷5 =8 feet

Standard deviation of the trees at Yard works = ∑(║(height of the tree-mean height of the tree))║/(number of trees)

(height of the tree-mean height of the tree)= ║(7-8)║+║(9-8)║+║(7-8)║+║(12-8)║+║(5-8)║ = (1)+1+(1)+4+(3)= 10

Therefore standard deviation = (10)/(5) =2

2). In the same way mean height of the trees at Grow Station=(9+11+6+12+7)/5= 45/5 = 9

Now we will calculate the mean deviation of the tress at Grow Station

= ∑║(height of the tree-mean height of the tree)║/(number of trees)

= ║(9-9)║+║(11-9)║+║(6-9)║+║(12-9)║+║(7-9)║/(5)

= (0+2+3+3+2)/5

= 10/5 =2

Therefore The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

                                                             

7 0
4 years ago
Read 2 more answers
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