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3 years ago

Please answer fjdjddn

Mathematics

1 answer:

Sveta_85 [38]3 years ago

6 0

To protect national security

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The sum of two integers is 81.if the product is 1088.what are the integers

arlik [135]

Answer:

(a;b)={(17; 64); (64; 17)}

Step-by-step explanation:

a+b=81 => b=81-a

a*b=1088

a*(81-a)=1088

-a²+81a=1088

a²-81a+1088=0

a²-64a-17a+1088=0

a(a-64)-17(a-64)=0

(a-17)(a-64)=0

=> a=17 and a=64

for a=17 => b=81-17=64

for a=64 => b=81-64=17

(a;b)={(17; 64); (64; 17)}

3 0

3 years ago

Fill the table using this function rule.

ElenaW [278]

Y=29-2(1)
y=29-2=27
(1,27)
y=29-2(3)
y=29-6=23
(3,23)
y=29-2(4)
y=29-8=21
(4,21)
y=29-2(5)
y=29-10=19
(5,19)

7 0

3 years ago

Heh its me again I NEED HELPPPPPPPPP

kari74 [83]

Answer:

1st and 3rd and 5th

Step-by-step explanation:

5 0

3 years ago

Alex has 235 candies. He wants to place the candies in five equal groups. How many candies will Alex place in each group?

Bad White [126]

Answer:

A.47

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Please help with 11c!?

Contact [7]

Answer:

"To the nearest year, it would be about 9 years"

Step-by-step explanation:

11c)

This is compound growth problem. It goes by the formula:

$F=P(1+r)^t$

Where

F is the future amount

P is the present (initial) amount

r is the rate of growth, in decimal

t is the time in years

Given,

P = 20,000

r = 8% = 8/100 = 0.08

F = double of initial amount = 2 * 20,000 = 40,000

We need to find t:

$F=P(1+r)^t\\40,000=20,000(1+0.08)^t\\2=(1.08)^t$

To solve exponentials, we can take Natural Log (Ln) of both sides:

$2=(1.08)^t\\Ln(2)=Ln((1.08)^t)$

Using the rule shown below we can simplify and solve:

$Ln(a^b)=bLn(a)$

We can write:

$Ln(2)=Ln((1.08)^t)\\Ln(2)=tLn(1.08)\\t=\frac{Ln(2)}{Ln(1.08)}\\t=9.0064$

To the nearest year, that would be about 9 years

5 0

3 years ago