Answer:
The vertex is (-3,1)
Step-by-step explanation:
Here, we want to write the given function in the vertex form
Mathematically, we have this as;
y = a(x-h)^2 + k
where the vertex is (-h,k)
Thus, we have
Let us divide the coefficient of x by 2, square and add to both sides ; prior to this, we will equate y to 0
Thus, we have it that;
0 = x^2 + 6x + 10
x^2 + 6x + 10 + 9 = 9
x^2 + 6x + 9 = 9-10
x^2 + 6x + 9 = -1
(x + 3)^2 = -1
(x + 3)^2 + 1 = 0
So the vertex here as represented by (-h,k) is;
(-3,1)
You use the equation a²+b²=c²
c = the hypotenuse
a and b represents the legs
Here are two examples
Example 1
Side a = 6
Side b = 8
6²+8²=c²
Square the legs
36+64=x²
Sdd
100= x²
Now we use the square root to find x
√100=√x
Solve the square root
10 = x
Example 2
side a = 3
hypotenuse = 7
3²+x²=7²
Square the known numbers
9+x²=49
Subtract 9 from 49
x²=40
Find the square root
√x=√40
x= 6.32 or 2√10
Hope this helps :)
Answer:
x squared over 16 minus y squared over 25 equals 1
Step-by-step explanation:
x²/4² - y²/5² = 1
x²/16 - y²/25 = 1
Answer:
Udjdjerjrkr so ha
Step-by-step explanation:
