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3 years ago

Plz ans this question quick

Mathematics

1 answer:

Ivanshal [37]3 years ago

6 0

Answer:

i. $553.18 ii. 51,860 NRs

Step-by-step explanation:

1 American dollar = 103.72 NRs

i. to get American dollars from NRs you would do

57,376 NRs ÷ 103.72 NRs

ii. to get NRs from USD you would do the opposite for the first one

500 USD × 103.72 NRs

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The variable r is directly proportional to the square of t, and r = 144 when t = 72.

Paul [167]

Answer:

k=0.023

Step-by-step explanation:

$r \alpha {t }^{2} \\ r = k {t}^{2} \\ 144 = k \times {72 }^{2} \\ k = \frac{144}{ {72 }^{2} } \\ k = 0.023 \\ the \: eqn \: is \: therefore \\ r = 0.023 \times {t}^{2}$

4 0

3 years ago

A line passes through the origin and the point (3,5). What is the slope of the line?

masha68 [24]

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 0}}\quad ,&{{ 0}})\quad 
% (c,d)
&({{ 3}}\quad ,&{{ 5}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{5-0}{3-0}$

4 0

3 years ago

If sin theta = 2/5 and theta is in quadrant I, determine the following.

anzhelika [568]

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{2}}{\stackrel{hypotenuse}{5}}\impliedby \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-b^2}=a \qquad \begin{cases} c=\stackrel{hypotenuse}{5}\\ a=adjacent\\ b=\stackrel{opposite}{2}\\ \end{cases} \\\\\\ \pm\sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a\implies \stackrel{I~Quadrant}{+\sqrt{21}=a}$

recall that cosine is positive on the I Quadrant, so though we get a ± valid roots, only the positive one applies.

$\bf cos(\theta)=\cfrac{\stackrel{adjacent}{\sqrt{21}}}{\stackrel{hypotenuse}{5}} \\\\\\ tan(\theta)=\cfrac{\stackrel{opposite}{2}}{\stackrel{adjacent}{\sqrt{21}}} \qquad \qquad cot(\theta)=\cfrac{\stackrel{adjacent}{\sqrt{21}}}{\stackrel{opposite}{2}} \\\\\\ csc(\theta)=\cfrac{\stackrel{hypotenuse}{5}}{\stackrel{opposite}{2}} \qquad \qquad sec(\theta)=\cfrac{\stackrel{hypotenuse}{5}}{\stackrel{adjacent}{\sqrt{21}}}$

now, for tangent and secant, let's rationalize the denominator.

$\bf tan(\theta)\implies \cfrac{\stackrel{opposite}{2}}{\stackrel{adjacent}{\sqrt{21}}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{21} \\\\\\ sec(\theta)\implies \cfrac{\stackrel{hypotenuse}{5}}{\stackrel{adjacent}{\sqrt{21}}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{5\sqrt{21}}{21}$

5 0

3 years ago

Please answer this correctly

Diano4ka-milaya [45]

Answer:

3/4

Step-by-step explanation:

The numbers odd or less than 3 are 2, 3, and 5.

3 numbers out of 4.

P(odd or less than 3) = 3/4

3 0

4 years ago

Coach Burns charted the change in his runners’ 5K times from the first race of the year to the second race of the year. Which st

Andrews [41]

Answer:

Student a

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Plz ans this question quick ​

Plz ans this question quick