Answer:
$950 in order to maximize the revenue.
Explanation:
The computation of monthly rent in order to maximize revenue is shown below:-
R (x) = Rent price per unit × Number of units rented
= ($900 + $10 x) × (100 - x)
= $90,000 - 900 x + 1000 x - 10 x^2
R (x) = -10 x^2 + 100 x + $90,000
Here to maximize R (x), we will find derivative and equal it to zero
R1 (x) = -20 x + 100 = 0
20 x = 100
x = 5
Therefore the monthly rent is p(5) = $900 + 10(5)
= $900 + 50
= $950 in order to maximize the revenue.
The answer to the given statement above is false, it is because even if a person has entered a partnership, it does not mean less work and effort should be done to maintain the relationship because having no effort in maintaining this relationship could only cause the bond to diminish and destroy. It is best to have an equal amount of work done in order to maintain a relationship with the partner.
Answer:
si, goo gagag goo gaga
Explanation:
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