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Anettt [7]
4 years ago
14

Match the width with the given area and length of a rectangle.

Mathematics
1 answer:
torisob [31]4 years ago
3 0

Answer:

5 cm A = 44cm; <u>w</u><u> </u><u>=</u><u> </u><u>8</u><u>.</u><u>8</u><u> </u><u>cm</u>

7.5 cm A = 48.75 cm2; <u>w</u><u> </u><u>=</u><u> </u><u>6.5</u><u> </u><u>cm</u>

5 cm A = 31.25; <u>w</u><u> </u><u>=</u><u> </u><u>6</u><u>.</u><u>2</u><u>5</u>

9.25 cm A = 55.5 cm; <u>w</u><u> </u><u>=</u><u> </u><u>6</u><u> </u><u>cm</u>

Step-by-step explanation:

What you have to do to find the answer is to take the length which for the first problem is 5 cm and then multiply the 5 by each width until you get the area. Example; Length <em>x</em> Width = Area

Basically you use the length times all of the widths until you match up the area.

Hope I could help

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3 years ago
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Step-by-step explanation:

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3 years ago
A ball is shot from a cannon into the air. The equation that's gives the height (h) of the ball of any time (t) is: h(t)= -16t^2
Gre4nikov [31]

Answer:

26.5 units

Step-by-step explanation:

The height of the ball at any time t is given by :

h(t)= -16t^2 + 40t + 1.5 ...(1)

We need to find the maximum height of the ball.

For maximum height, put \dfrac{dh}{dt}=0

i.e.

\dfrac{d( -16t^2 + 40t + 1.5)}{dt}=0\\\\-32t+40=0\\\\t=\dfrac{40}{32}\\\\t=1.25\ s

Put t = 1.25 in equation (1) to find the maximum height.

So,

h(t)= -16(1.25)^2 + 40(1.25) + 1.5\\\\=26.5\ units

So, the maximum height reached by the ball is 26.5 units.

4 0
3 years ago
Answer -7 x (-9) = ?<br><br>Thank You!
artcher [175]
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because  if we multiply  negative by negative we obtain +</span>
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Steps to describe an inscribed regular hexagon.
Rus_ich [418]

Answer:

many sides

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