From the function given:
y=x^2-5
this can be written as:
y=x^2+0x-5
writing in vertex form we get:
y=(x-h)^2+k
where: (h,k) is the vertex
y=(x-0)^2-5
thus the vertex is at (0,-5)
the parent function is y=x^2, thus the graph of the parent function is First graph
Can't read it it's blurry. Sorry.
Answer:
Step-by-step explanation:
I don't know
Answer:
THE CORRECT OPTION IS A) Δ ABC
Δ BDC
Δ ADB
Step-by-step explanation:
The first option is in correct order of triangle ,we can easily the their sides are proportionate . And having eqal angles.