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Irina18 [472]
3 years ago
13

A building 250 feet tall casts a 60 foot long shadow. If a person looks down from the top of the 1)_______ building, what is the

measure of the angle between the end of the shadow and the vertical side of the building (to the nearest degree)? (Assume the person's eyes are level with the top of the building.)
A) 14
B) 77
C) 76
D) 13

Mathematics
1 answer:
Rashid [163]3 years ago
3 0

Answer:

D) 13

Step-by-step explanation:

Let x represent our required angle.

Please find the attachment.

We have been given that a 250 feet tall building casts a 60 foot long shadow.

We can see from our attachment that 60 is opposite side and 250 is adjacent side to angle x. We also know that tangent relates opposite side of a right triangle with its adjacent side.

\text{tan}=\frac{\text{Opposite}}{\text{Adjacent}}

\text{tan}(x)=\frac{60}{250}

\text{tan}(x)=\frac{6}{25}

Now, we will use arctan to solve for x as:

x=\text{tan}^{-1}(\frac{6}{25})

x=13.49573328^{\circ}

Round to nearest degree:

x\approx 13^{\circ}

Therefore, the measure of the angle between the end of the shadow and the vertical side of the building is 13 degrees.

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Step-by-step explanation:

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2 years ago
"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen
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Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }]

Where

p' is the sample proportion/point estimator of the population proportion

Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} } is the margin of error (d) of the confidence interval.

Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648

So

d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }

d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }

(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}

n*(d*Z_{1-\alpha /2})^2= p'(1-p')

n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}

n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}

n= 147.28 ≅ 148 boxes.

I hope it helps!

3 0
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Step-by-step explanation:

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Since the slope is \frac{3}{4}, we see that the negative reciprocal slope is -\frac{4}{3}, as \frac{4}{3} is the reciprocal (flip the numerator and denominator).

From here, we can use point slope form: y - y1 = m(x- x1), where (y1, x1) is  the point. In this case, (3, 1) is the point.

Thus, we have: y-1 =-\frac{4}{3}(x-3) as our final equation.

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Let me know if this helps!

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2 years ago
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